, for S > 2 and n > 2 i stumbled on this set while doing some mappings of figurate numbers, Fs,n. i have defined as Non-Figurate any integer that is not a solution to the above generalized equation for figurate numbers, for integer variable values s>2 & n> 2. (i have looked, but failed, to find any mention of this set, so if it is known and/or has a different name, somebody stop me.
the serendipitous find of those non-figurate elements listed above, came by viewing a verbose list of all solutions Fs,n to s=10 & n=20 and noticing the elements as missing.
certainly one approach is a program that mimics my method, i.e. finding all figurate numbers up to a certain value using the equation and then looking to see what integers are absent. my programming skills and resources are sorely lacking to progress this on my own any further than i have, and so part of my appeal here is to programmers for help.
another course might be to go at it algebraically, though this has the scent of diophantine jugglings if i am not mistaken. not exactly my expertise either.
Note: somewhere here at hypog we once had a discussion about the order of operations and parentheses in the generalized equation as i wrote it.
if that Latex representation above has an order of operations error that gives the wrong anwser, or if their is a more clear way to represent it, please pop in & correct me.
that's it for now. ....................
******************* Conclusions Summary Index *************************
under construction...
proposition:
proposer:
proof:
proofer:
posteriors:
posteriorer:
*************************
proposition: there exists a set of natural numbers that do not have [integer] solutions [n,s],n={3,4,5,...}, s={3,4,5,...} to the generalized equation for polygonal numbers P=1/2(n2s-2n2-ns+4n)
proposer: turtle [ post #1 ]
proof: observation of verbose list of polygonal numbers
proofer: turtle [ post #1 ]
posteriors: defined set denominated "non-polygonal numbers"
posteriorer: turtle
posteriors: extended listings of non-polygonal set elements
posteriorers: modest, jay-q, donk, phillip
******************************
proposition: all prime numbers belong to the set of non-polygonal numbers
proposer: turtle [ post #12 ]
proof: yes
proofer: Kharakov [ post #307 & #309 ]
proofer: qfwfq [ post #314 ]
posteriors: a fundamental conclusion on the set of non-polygonals.
posteriorers: concensus
**************************
proposition: find a method to determine if a natural number is polygonal and if so in how many ways.
proposer: diophantus
proof: yes. method given
proofer: donk [ post #32 ]
posteriors: a fundamental method
posteriorer: concensus
****************************
proposition: all prime powers of 2 belong to the set of non-polygonal numbers.
proposer: turtle [ post #4 ]
proof: none
proofer: none
posteriors: the propositon is confirmed by inspection to 2279
posteriorer: modest [ post# 61 ]
****************************
proposition: no multiples of 3 belong to the set of non-polygonal numbers.
proposer: turtle [ post #314
turtle said:
of the Katabatak table for figurate numbers eliminate a good number of possibilities for n. On the assumption that no non-figurate numbers have K transforms of 3 , 6 , or 9 (in base ten), then from the table we see three columns have only these transforms, and because the pattern is infinitely repeated over the set of integers we can conjecture that no indices in n of the forms (9m-6), (9m-3), or (9m) need trying.
This is in retrospect tantamount to saying that any number divisible by 3 is figurate.
proposer: donk [ post #100 ]
donk said:
No non-figurate number is divisible by 3.
proof: yes.
proofer: turtle [ post #103 ]
posteriors: a fundamental conclusion on the set of non-polygonal numbers
posteriorer: concensus
**********************
proposition: any non-polygonal number divisible by 5 is divisible by 10.
proposer: donk [ post #100 ]
proof: yes
proofer: searching...
posteriors:
posteriorer:
*************************
proposition: all even non-polygonal numbers have the form 6n+2
proposer: idmclean [ post # 199 ]
proof: yes
proofer: turtle [ post #? ]
posteriors:
posteriorer:
** through post #338

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![F=(n/2)*\left[ (s-2)*n-s+4 \right]](http://scienceforums.com/latex/img/dab820a248e9b195a4b005803b8a3bef-1.png)


to get rid of the rows I got:
and the other numbers can be related to that number by dividing it by two, adding one half, then multiplying it by the original number. So, I got:![\left( \frac{1}{2} i + \frac{1}{2} \right)i + n \left[i \left( \frac{1}{2} i + \frac{1}{2} \right) - i \right]](http://scienceforums.com/latex/img/33243dfb975b9317f7208bd6a3acc599-1.png)

and 











