Nootropic Posted February 18, 2007 Report Posted February 18, 2007 I know that boiling points of solutions containing volatiles solutes are actually depressed, but would this imply that the freezing point of a solution (say, oh, containing methanol or ethanol) with a volatile solute would be elevated? I can't seem to find anything to guarantee my thinking. Anybody? Quote
ronthepon Posted February 18, 2007 Report Posted February 18, 2007 If you're adding Volatile chemical #2 to V.C.#1, then the resulting solution may have a higher vapour pressure. That will only be when pure V.C.#2 has a greater Vapour pressure than pure V.C.#1 It's as simple as that. Assuming ideality in solution formation, addition of a more volatile solute will increase the vapour pressure. Quote
Nootropic Posted February 18, 2007 Author Report Posted February 18, 2007 I know the vapor pressure of the solution will increase, which in turn causes a decrease in boiling point ("boiling point depression") but I'm not sure if the increase in vapor pressure also causes an increase in the freezing/melting point of the solution ("freezing point elevation"). The solutions in question would be a water-ethanol and a water-methanol solution (water is the solvent); like I said, I know for sure that the boiling point is lower than that of pure water, but I don't know if the freezing point would be greater than that of pure water. Quote
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