bluesky Posted April 11, 2007 Report Posted April 11, 2007 Consider a gravity free hall in which a tray of mass M,carrying a cubical ice block of mass m and edge L,is at rest in the middle.If the ice melts,what would be the displacement of the system? I think it has to do with the conservation of momentum,since no external force is acting.But i cannot think further.Please help. Quote
bluesky Posted April 11, 2007 Author Report Posted April 11, 2007 I think I have got the answer.F=M(d^2R_cm/dt^2)=dP/dt=oTo have even a uniform motion of CM,what we need is a motion of CM from the rest.That must involve an acceleration.Since acceleration of CM is zero,we must conclude that CM did not move at all.Please check if I am correct. Quote
ronthepon Posted April 11, 2007 Report Posted April 11, 2007 Yes, the displacement of all the particles (the center of mass of the system will be zero. Quote
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