Jump to content
Science Forums

Recommended Posts

Posted

A rotating sphere contract slowly due to internal forces to (1/n)th of its original radius.What happens to its angular velocity.Show that increase in its energy equals the work done during its contraction.

 

(2/5)MR^2*w_1=(2/5)M(R/n)^2*w_2

 

From this we should find the change in w.

Regarding the workdone: Please help me to start with.

Posted

Well, what you have here is:

 

[math]\frac25 MR^2 w_1=\frac25 M(\frac{R}{n})^2 w_2[/math]

 

Can you see how the moment of inertia, [math]\norm\frac25 MR^2[/math], changes? Write the new one in terms of n and the old one and you should be able to get it.

Posted

Okay, using that we could go on to find the change in energy of the spinning sphere.

 

What I can't figure is how to analyse the work done in contracting the spinning sphere. (Other than talk about the law of conservation of energy)

Posted

Obviously the work must be equal to the change in kinetic energy, therefore the integral of centrifugal forces in dr must equal the difference.

 

Perhaps your difficulty is due to asking about potential energy. Yep, that requires a spot of careful thinking.... :)

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
×
×
  • Create New...