bluesky Posted June 3, 2007 Report Posted June 3, 2007 In the context of elliptical polarization,every book writes out this formula: (E_y/E_0y)^2 + (E_x/E_0x)^2 -2(E_y/E_0y)(E_x/E_0x) cos ε= (sinε)^2 where ε is the initial phase difference. After that they write this is the equation of an ellipse making an angle α with the E_x-E_y co-ordinate system such that tan 2α=[[2E_0x*E_0y]cos ε]/[(E_0x)^2 - (E_0y)^2] This is NOt a homework problem;but I want to clarify how does the 2nd relation concering tan 2α comes. I tried to understand by expanding tan 2α and by dividing RHS by (E_0x)^2 throught.But the factor cos ε is annoying. Can anyone please tell how the relation comes? Quote
Qfwfq Posted June 4, 2007 Report Posted June 4, 2007 You might facilitate response by using our LaTeX feature for the equations. Quote
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