sanctus Posted June 4, 2007 Report Posted June 4, 2007 Ok this might just be because I worked almost non-stop for ten hours, but how do you solve the following differential equation for E(t)?[math]\frac{dE}{dt}+\frac{da(t)}{dt}/a(t)\cdot E(t)[/math] It's easy to see that the solution is proportional to 1/a(t), but how do you actually find it? Quote
Qfwfq Posted June 5, 2007 Report Posted June 5, 2007 I'm not sure how to read the equation. Is the whole thing = 0 and are a and E both in the denominator? Quote
sanctus Posted June 5, 2007 Author Report Posted June 5, 2007 Yes i forgot the =0 and E(t)is not in the denominator:[math] \frac{dE(t)}{dt}+\frac{\frac{da(t)}{dt}}{a(t)} \cdot E(t)=0[/math] Sorry for that. Quote
Qfwfq Posted June 5, 2007 Report Posted June 5, 2007 No problem. :) Have you tried writing it as follows? [math]\frac{d\ln E(t)}{dt}+\frac{d\ln a(t)}{dt}=0[/math] Quote
sanctus Posted June 5, 2007 Author Report Posted June 5, 2007 No until now, but in this way I see now how it works.Thanks very much. Quote
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