Buffy Posted August 7, 2007 Report Posted August 7, 2007 [math]E=mc^2[/math] [math]\frac{1}{mc^2} \ \cdot \ E=mc^2 \ \cdot \ \frac{1}{mc^2}[/math] [math]\frac{E}{mc^2} = \cancel{mc^2} \ \cdot \ \frac{1}{\cancel{mc^2}}[/math] [math]\frac{E}{mc^2} = \frac{1}{1} = 1[/math] So, yah, 1. Mathematically speaking,Buffy Quote
Kutan Posted August 8, 2007 Report Posted August 8, 2007 So wait.. What's the difference, whether or not it's equal to 0 or 1? I figure the equation works and that's really all that matters, right? Quote
alexander Posted August 9, 2007 Report Posted August 9, 2007 no not at all, its not that equation works that matters, its HOW and WHY it works that you should be asking yourself! Quote
Agen Posted August 12, 2007 Report Posted August 12, 2007 E=mc2 is like 8=4x2 8 / 4x2 = 8/8=1 mhmh...:shrug: Quote
Kutan Posted August 14, 2007 Report Posted August 14, 2007 I figured if something equals something, they're going to equal 1.. Not 0. : Quote
sanctus Posted August 14, 2007 Report Posted August 14, 2007 Maybe it was more a philosophical question than a mathematical, that's why I asked why he thinks it should be zero.... Quote
Tormod Posted August 14, 2007 Report Posted August 14, 2007 Does it equal zero or one? AFAIK, whenever you take a statement that says X=Y (in any form or shape), then X/Y will have to be 1. If the values are zero we get 0/0 which would also be 1, although there is a slightly philosophical twist to that one. Quote
sanctus Posted August 16, 2007 Report Posted August 16, 2007 Actually 0/0 is indermined. YOu can say it is 1 because 1*0=0 but I can say it is 123.121212 because 123.121212*0=0...this is just the intuitive proof. Quote
Tormod Posted August 16, 2007 Report Posted August 16, 2007 Well, let me rephrase...0/0 "could" get you 1 as well. :weather_storm: Quote
ryan2006 Posted August 21, 2007 Author Report Posted August 21, 2007 1/1=1 0/0=0 what is the value you place on E=MC2 I thought both somehow but it does seem to be more of a phisopcal question or perhaps a matrix of 1's and 0's Quote
Tormod Posted August 21, 2007 Report Posted August 21, 2007 what is the value you place on E=MC2 c squared is the speed of light in vacuum, or 300,000,000 m/second, times itself. So it's a huge figure: 8.98755179*10^16 m^2/s^2. Using this as a constant in the equation means that E and m are variables, and the implication is that a *lot* of energy is yielded by a tiny amount of matter. It also takes a *lot* of energy to create matter. The formula says nothing about the speed or method of conversion, nor does it give any values for E or m. So the examples of 1 and 0 above are just figurative. Since E=mc^2 is basically the same as saying x=y, then 1=1 is *equally valid* - but it is not the *same* equation. I'm probably just confusing this more so I'll shut up now. :pirate: Quote
Qfwfq Posted August 27, 2007 Report Posted August 27, 2007 although there is a slightly philosophical twist to that one.Slightly philosophical? ...the implication is that a *lot* of energy is yielded by a tiny amount of matter. It also takes a *lot* of energy to create matter.No, it's that we use such tiny units of energy, except for those such as gramme, kilogramme etc. Anyway the answer to the original question is: 1 according to the rest frame and more than 1 according to other frames. Quote
Tormod Posted August 27, 2007 Report Posted August 27, 2007 No, it's that we use such tiny units of energy That's just because people in southern Europe are so, uhm, unassuming (relatively speaking). Quote
OldBill Posted August 28, 2007 Report Posted August 28, 2007 OK Guys - Let's not let this get out of hand. It's pretty simple: E divided by MC2 = 1; E minus MC2 = 0 There, now both one and zero are involved in variants on Einstein....Ryan should be happy, and the rest of you might consider not thinking 'zebras' every time you hear hoof beats. Quote
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