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Posted

You have gone back in time and are working with Dalton. He is working on a table of relative masses, and these are his data:

 

0.602 g gas A reacts with 0.295 g gas B

0.172 g gas B reacts with 0.401 g gas C

0.320 g gas A reacts with 0.374 g gas C

 

a. Assuming simplest formulas (AB, BC, AC), construct a table of relative masses for Dalton. (What do I have to do with this ?)

 

Knowing some history of chemistry, you tell him that if he finds the volumes of the gases at equal temperature and pressure, he doesn't need to assume simplest formulas. You collect these data:

 

6 volumes gas A + 1 volume gas B= 4 volumes product

1 volume gas B + 4 volumes gas C= 4 volumes product

3 volume gas A + 2 volumes gas C= 6 volumes product

 

b. Write out the simplest balances equations, and find the actual relative masses of the elements.

 

I have no idea on how to solve this problem. Please help me!

  • 2 weeks later...
Posted

a:b:c is 0.602 : 0.295: 0.68776

sol.

a:b = 0.602 : 0.295

b:c = 0.172 : 0.401

 

you must convert b in eq1 = b in eq2 by x0.295/0.172

 

b:c = 0.172*0.295/0.172 : 0.401*0.295/0.172

= 0.295 : 0.68776

a:b = 0.602:0.295

b:c = 0.295:0.68776

a:b:c = 0.602:0.295:0.68776

 

another question, i don't know

 

goodluck with your apchem

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