Chiyuki_Snow Posted August 19, 2007 Report Posted August 19, 2007 You have gone back in time and are working with Dalton. He is working on a table of relative masses, and these are his data: 0.602 g gas A reacts with 0.295 g gas B0.172 g gas B reacts with 0.401 g gas C0.320 g gas A reacts with 0.374 g gas C a. Assuming simplest formulas (AB, BC, AC), construct a table of relative masses for Dalton. (What do I have to do with this ?) Knowing some history of chemistry, you tell him that if he finds the volumes of the gases at equal temperature and pressure, he doesn't need to assume simplest formulas. You collect these data: 6 volumes gas A + 1 volume gas B= 4 volumes product1 volume gas B + 4 volumes gas C= 4 volumes product3 volume gas A + 2 volumes gas C= 6 volumes product b. Write out the simplest balances equations, and find the actual relative masses of the elements. I have no idea on how to solve this problem. Please help me! Quote
liger Posted August 29, 2007 Report Posted August 29, 2007 a:b:c is 0.602 : 0.295: 0.68776sol.a:b = 0.602 : 0.295b:c = 0.172 : 0.401 you must convert b in eq1 = b in eq2 by x0.295/0.172 b:c = 0.172*0.295/0.172 : 0.401*0.295/0.172 = 0.295 : 0.68776a:b = 0.602:0.295b:c = 0.295:0.68776a:b:c = 0.602:0.295:0.68776 another question, i don't know goodluck with your apchem Tormod 1 Quote
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