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Photons, if wavelength, then amplitude ?


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Posted

I may have an uneasy beginning at this site, but I trust everyone will be patient. I wonder if an electron, after some acceleration, gives off a photon with a wavelength proportional to the acceleration, is there an amplitude proportional to the strenght of the magnetic field of the electron ?

Posted
I may have an uneasy beginning at this site, but I trust everyone will be patient.
We’re a famously friendly and patient site – a friendly forum for friendly folk :) Welcome!
I wonder if an electron, after some acceleration, gives off a photon with a wavelength proportional to the acceleration, is there an amplitude proportional to the strenght of the magnetic field of the electron ?

Simple answer: no.

 

First, it’s important to look step-by-step at your post, and make sure each step is sensible and correct:

an electron, after some acceleration, gives off a photon with a wavelength proportional to the acceleration
Accelerate an electron – that is, change its velocity by some measurable quantity over a measurable interval of time – it will may emit a photon. The photon, however, has a wavelength not proportional to the acceleration, but to the change in energy of the photon, as given by

[math]\Delta v = \frac{\Delta E}{h}[/math], where [math]v[/math] is the photon’s frequency, [math]E[/math] its energy, and [math]h[/math] Planck’s contant.

[math]\Delta E[/math] is related to the electron’s before and after speed [math]u_1[/math] and [math]u_2/math] by

[math]\Delta E = m_e \left( \frac1{\sqrt{1-\left( \frac{u_1}{c}\right)^2}} -\frac1{\sqrt{1-\left( \frac{u_2}{c}\right)^2}} \right)[/math], where [math]m_e[/math] is the rest mass of an electron and [math]c[/math] the speed of light in vacuum.

 

You can work all this out to find the frequency (for a visible one, its color) of a photon for any given [math]u_1[/math] and [math]u_2/math]. The various things that can change the speed of an electron have characteristic emitted photon frequencies and names of the emitted photons like Bremsstrahlung, Čerenkov radiation, and Cyclotron radiation. Figuring out why these various causes produce characteristic a [math]u_1[/math] and [math]u_2[/math] is complicated.

 

The last part of the post is less complicated.

is there an amplitude proportional to the strenght of the magnetic field of the electron ?
Short answer: no.

 

The energy of a photon doesn’t have an amplitude term in its formula, only a frequency term:

[math]E = hv[/math]

 

Amplitude, such as is used to carry an AM radio signal, isn’t a characteristic of each photon, but of the number of photons emitted in a given interval. The simplest sort of Amplitude modulation is a “none or lots” scheme. A useful (and exact) analogy is that frequency is color, and amplitude is brightness, of a electromagnetic signal.

 

This isn’t very welcoming chatter for an introduction, so why don’t you tell us something about yourself, your interests, etc, aytche? I’ll move the technical stuff to the physics & math forum after this thread has got some more friendly hellos.

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