Intergration

[pigeon_soup]

Hey guys :)

 

I have a peice of homework to do from college

i have an equation in the format:

a((bx^n)+cx)

and i need to intergrate it.

 

Intergrate as in reverse of differentiation aka antiderivative.

 

many thanks to anyone who can help.

[modest]

It would be helpful if you gave us some more information. What equation are you trying to integrate? What steps have you taken to integrate it? Is there a particular step, technique, or rule that's giving you trouble?

 

For posting equations you can use latex which is explained and discussed in this thread:

http://hypography.com/forums/physics-mathematics/6576-latex-fomulas-math-v2-0-a.html

 

-modest

[freeztar]

Hello, and welcome to Hypography. :)

 

Can you show what you have worked out so far?

[pigeon_soup]

ok here goes :S

 

frac{dy}{dy} = fract {9}{32} (x^2 -4x)

[pigeon_soup]

[math]\frac{dy}{dy} = \frac {9}{32} (x^2 -4x)[/math]

 

I need to get this to the format y= blah blah blah using intergration.

[modest]

ok,

 

[math]\int \frac{9}{32}(x^2 - 4x)dx[/math]

 

 

What do you think your first step would be?

[Nootropic]

It depends on your preference as to what the first step would be. You can either choose to put 9/32 "outside" of the integral, which is one of the rules of integrating or you can distribute the 9/32 so that you have 9/32 * x^2 -9/8*x. Now with either step done, we know that when we are integrating a linear combination of continuous function, we can integrate each function separately. So if you performed the "first step" the second way, then you would integrate 9/32 * x^2 and -9/8*x separately. If you have a polynomial of degree n, for any natural n, so x^n, then it's integral is x^n+1/(n+1).

 

Here's a page that gives detailed explanations

 

Indefinite Integration of Polynomials

[Nootropic]

and don't forget indefinite integration produces a constant that gets added onto the function you just integrated.