UncleAl Posted July 8, 2009 Report Posted July 8, 2009 For your amusement... (pi)^4 + (pi)^5 = e^6e^[pi(sqrt163)] = (640,320)^3 + 744 13^5 + 16^5 = 17^5 + 1213 + 16 = 17 + 12 31, 331, 3331, 33331, 333331, 3333331, 33333331... are primesn^2 + n + 41 generates primes (3,472,073)^7 + (4,627,011)^7 = (4,710,868)^7 Goodbye Fermat's Last theorem 4 - 10 = 9 - 15Add 25/4 to both sides,4 - 10 + 25/4 = 9 - 15 + 25/4Write sides as complete squares,(2 - 5/2)^2 = (3 - 5/2)^2Take the square root of both sides2 - 5/2 = 3 - 5/2,add 5/2 to both sides2=3 Quote
lawcat Posted July 8, 2009 Report Posted July 8, 2009 But really, f (2) = f (3) I agree: bad math. Funny things happen when you go from linear to quadratic. Quote
Qfwfq Posted July 10, 2009 Report Posted July 10, 2009 But really, f (2) = f (3) I agree: bad math. Funny things happen when you go from linear to quadratic.Such as the fact that a and -a have the same square. :D Quote
lawcat Posted July 10, 2009 Report Posted July 10, 2009 Such as the fact that a and -a have the same square. :D Yes. Does that not tie to negative and positive Lorentz factor in the antimatter blackhole thread. Quote
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