How this is possible?

[buddha elämuni]

The distance to Earth 10 light-years.

 

Moving almost at the speed of light towards the Earth and the Earth in one year, your time is spent on just one second.

 

Findings Globe and see the Earth rotating under the sun, you second.

 

When you measure what kind of trip Globe is moving under you per second, you will notice the earth moving a lot more than the speed of light.

 

This should not be possible in your theory appropriate. Still, this is your theory appropriate?

 

a contradiction!

[Boerseun]

The distance to Earth 10 light-years.

From where?

Moving almost at the speed of light towards the Earth and the Earth in one year, your time is spent on just one second.

If you're travelling anywhere at close to the speed of light, you will experience time dilation.

Findings Globe and see the Earth rotating under the sun, you second.

I don't understand what you're trying to say here.

When you measure what kind of trip Globe is moving under you per second, you will notice the earth moving a lot more than the speed of light.

From whatever frame of reference you're looking at the Earth, you will not see it moving at faster than the speed of light.

This should not be possible in your theory appropriate. Still, this is your theory appropriate?

What theory are you even referencing here? :thumbs_up

a contradiction!

No. Incomprehensible, your post is. Confused, am I.

[RevOfAllRevs]

If you're travelling anywhere at close to the speed of light, you will experience time dilation.

 

Maybe you meant 'If you're traveling anywhere at close to the speed of light, you will experience noticeable time dilation'. Any two (or more) objects in motion (and a object in some other circumstances ie near gravity wells) will experience time dilation relative to each other. You are correct in that as the velocity (relative to each other) nears light speed the effects will become profound. However even at very slow speeds (not even as fast as the escape velocity of the earths gravity well) the time dilation effects are measurable.

 

; }>

[Boerseun]

Maybe you meant 'If you're traveling anywhere at close to the speed of light, you will experience noticeable time dilation'.

Well, that goes without saying. But my answer was a direct answer to the line posted by the OP:

Moving almost at the speed of light towards the Earth and the Earth in one year, your time is spent on just one second.

and should be obvious.

[modest]

The distance to Earth 10 light-years.

 

Moving almost at the speed of light towards the Earth and the Earth in one year, your time is spent on just one second.

 

Findings Globe and see the Earth rotating under the sun, you second.

 

When you measure what kind of trip Globe is moving under you per second, you will notice the earth moving a lot more than the speed of light.

 

This should not be possible in your theory appropriate. Still, this is your theory appropriate?

 

a contradiction!

 

Yes, the earth would superficially appear to move "faster than light"—although never would the earth appear to overtake a photon. The reason for this appearance is Doppler shift.

 

The observed frequency of the earth orbiting the sun in that situation is:

 

[math]F_\mathrm{ship} = F_\mathrm{rest}\sqrt{\left({1 + v/c}\right)/\left({1 - v/c}\right)}[/math]

 

[math]F_\mathrm{ship}[/math] is the amount of times per year that the earth is seen to orbit the sun from the ship. It's what the ship observes. [math]F_\mathrm{rest}[/math] is the amount of times per year that the earth orbits in its rest frame (1 time). [math]v[/math] is the speed at which the earth/sun system is approaching the ship (or the speed of the ship relative to the sun).

 

As v approaches c (as the ship nears the speed of light relative to the sun) the frequency on the ship goes to infinity. In other words: the earth will go around in circles really, really fast. This isn't a paradox, it is what we should expect considering Doppler shift and time dilation.

 

If you wanted to know the actual orbit rate relative to your clock (rather than the blushifted observation) then you'd need to account for doppler shift. Doppler shift increases frequency by a factor of [math]1/(1 - v/c)[/math], so you would divide the fist equation by that factor (or multiply it by 1 - v/c) and you get:

 

[math]F_\mathrm{rest}\sqrt{\left({1 + v/c}\right)/\left({1 - v/c}\right)}\times \left(1 - v/c\right) = F_\mathrm{rest}\sqrt{1 - v^2/c^2}[/math]

 

and that's the good old fashion time dilation equation.

 

~modest