Partical Pressures, again

[hdawnw]

The partical pressure of methane is 0.175 atm and that of oxeygen is 0.125 in a mixture of two gases.

a) find mole fraction of each gas in the mixture.

:hihi: if the mixture occupies a volume of 10.5L at 65 C, calculate the total number of moles of gas in the mixture.

c) Calculate number of grams of each gas in the mixture.

[Jay-qu]

Is this a homework question hdawnw? we dont normally like to just give out answers because you wont learn anything from that. Show us your understanding of the problem and what needs to be done and where you are stuck, then we can help :hihi:

 

Its for your own good :dog:

[hdawnw]

I don't want the answer, I just need someone to tell me step by step how to do because I have zero clue how to start it.

[Jay-qu]

Ok well first off it is partial pressure, referring to the amount of pressure each element present contributes to the overall pressure. So the total pressure in this case is just the sum of the partial pressures:

0.175 + 0.125 = 0.300 atm

 

Now you can construct a ratio of partial pressure to the total pressure and this will give the fraction of each gas present by number (moles).

 

Now work that out and attempt the next two.