IDMclean Posted April 5, 2010 Report Posted April 5, 2010 I was reading about the Carnot heat engine the other day, and I noticed that Carnot's theorem looked oddly familiar. Like Lorentz factor familiar. I don't have much to say about this, but I do have a question. Is the following equivalence mathematically correct? Lorentz Factor[math]\gamma =\frac{1}{\sqrt{1-\frac{\nu^2}{c^2}}} = \frac{1}{\sqrt{1-\beta}}[/math] Carnot Efficiency[math]\eta=1-\frac{T_C}{T_H}=\frac{W}{Q_H}[/math] Hypothetical Lorentz-Carnot Efficiency Factor[math]\gamma =\frac{1}{\sqrt{1-\frac{\nu^2}{c^2}}} = \frac{1}{\sqrt{\eta}}=\frac{1}{\sqrt{1-\frac{T_C}{T_H}}}=\frac{1}{\sqrt{\frac{W}{Q_H}}}[/math] On a glance over a google search, I found this.A SPECIAL RELATIVISTIC HEAT ENGINE Quote
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.