Guest Aemilius Posted June 25, 2013 Report Posted June 25, 2013 (edited) Below is depicted a straight tube closed at one end and open at the other filled with fluid. The lower open end of the tube terminates beneath the surface of the fluid in the resevoir and the upper end is closed, preventing normal atmospheric pressure from acting on it. There is no externally applied magnetic field and gravity acting on the fluid is uniform (in the tube and the resevoir). In this situation nothing will happen.... the fluid level within the tube will not rise or fall. Gravity acting on the fluid is uniform (in the tube and the resevoir) and normal atmospheric pressure coming to bear on the surface of the fluid in the resevoir will exert pressure at the base of the water column created by the tube, keeping the water from just falling into the resevoir (as it would in a vacuum). The fluid will remain at rest. The sum of all the equal and opposite forces acting on the system will be zero.... static equilibrium. Edited June 26, 2013 by Aemilius Quote
Guest Aemilius Posted June 26, 2013 Report Posted June 26, 2013 (edited) Below is depicted the same straight tube closed at one end and open at the other filled with fluid. The lower open end of the tube terminates beneath the surface of the fluid in the resevoir and the upper end is closed as before, preventing normal atmospheric pressure from acting on it, but now with the 5 Tesla permanent magnet installed around it at about the middle of the tube providing an externally applied magnetic field. The fluid at rest within the tube immediately above the externally applied magnetic field will be diamagnetically repelled upward, and the fluid within the tube at rest immediately below the externally applied magnetic field will be diamagnetically repelled downward with a net gain of zero in either upward or downward force. In this situation nothing will happen.... the fluid level within the tube will not rise or fall. Gravity acting on the fluid is uniform (in the tube and the resevoir) and normal atmospheric pressure coming to bear on the surface of the fluid in the resevoir will exert pressure at the base of the water column created by the tube, keeping the water from just falling into the resevoir (as it would in a vacuum). Essentially it will behave just as if the magnet was never installed, with the same result as before.... The fluid will remain at rest within the tube. The sum of all the equal and opposite forces acting on the system will be zero.... static equilibrium. Edited June 26, 2013 by Aemilius Quote
Guest Aemilius Posted June 26, 2013 Report Posted June 26, 2013 (edited) I could continue to explore this, but at this point (with reference to posts 34 and 36), I'm just going to go ahead and jump to the conclusion that.... No imposition of any externally applied magnetic field any where along the length of the siphon in this scenario will result in any tendency on the part of the diamagnetic fluid within the tube to move in one direction or the other, whether the fluid be at rest or in motion. Fluid at rest within the siphon tube. Magnet installed on the right.... No effect. Fluid at rest within the siphon tube. Magnet installed on the left.... No effect. Fluid in motion within the siphon tube. Magnet installed on the right.... No effect. Fluid in motion within the siphon tube. Magnet installed on the left.... No effect. Edited June 26, 2013 by Aemilius Quote
Guest Aemilius Posted June 27, 2013 Report Posted June 27, 2013 (edited) Moontanman "Shouldn't you start your own thread for this?" Sorry for my knee jerk response to your suggestion. You're right. The idea I'm exploring, though similar, is different from the one that went before. It would be a good idea for me to start another thread for it. New thread.... Magnetically Enabled Continuous Circulation Of Diamagnetic Fluid Edited June 27, 2013 by Aemilius Quote
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