Guest liliangrn Posted April 22, 2005 Report Posted April 22, 2005 Hi Clay, So terminal velocity is dependant on the altitude of the surface you hit. The highest speed of terminal velocity would be when you hit water level. This is the closest to the centre of gravity you can fall. Unless the bottom of the grand canyon is below sea level. Do you know the altitude of the Grand Canyon? Josephine
C1ay Posted April 22, 2005 Report Posted April 22, 2005 Do you know the altitude of the Grand Canyon?I think I read somewhere that it is around 7000 feet....
Turtle Posted April 22, 2005 Report Posted April 22, 2005 ___The Grand Canyon is just over 1 mile deep at the deepest. I once hiked to the bottom and back while studying geology. It was 110 degrees F at the bottom; took me from 6 am to 6 pm. The trail in is not the trail out as the trail in has no water. ___Some of the oldest rock known (schist) on Earth is at the very bottom. I don't know what the altitude(rim or bottom) is. Death Valley however is some 50 feet below sea level if I remember correctly.___Light will bend inside glass when the incident ray is perpendicular to the surface. The type of glass determines the angle of bending. This also is why optical mirrors must be front surface mirrors & not the common back surface mirrors as in vanitys. ;)
Buffy Posted April 22, 2005 Report Posted April 22, 2005 ___Some of the oldest rock known (schist) on Earth is at the very bottom. I don't know what the altitude(rim or bottom) is. Death Valley however is some 50 feet below sea level if I remember correctly.Current actual altitude of course does not directly correllate to age, since as you well know, our tectonic plates are getting tossed up and down (know you know this Turtle, this is a clarification for the audience....) Cheers,Buffy
Turtle Posted April 22, 2005 Report Posted April 22, 2005 ___No no...of course not. We were talking about the altitude in relation to terminal velocities. The farther you fall the higher your terminal velocity.___I only threw in age because that's whats' at the bottom of Grand Canyon, some of the oldest rocks on Earth(about 3,5 billion years old schist if I recall.___The law of superimposition does hold in general however, ie the lower in the strata the older. One of the major breakthroughs in geology in its early beginnings in fact. ;)
Guest liliangrn Posted April 22, 2005 Report Posted April 22, 2005 Thanks Turtle, ___Some of the oldest rock known (schist) on Earth is at the very bottom. I don't know what the altitude(rim or bottom) is. Death Valley however is some 50 feet below sea level if I remember correctly. Can I make your job harder by asking is this at high tide or low tide? Just kidding. ___Light will bend inside glass when the incident ray is perpendicular to the surface. The type of glass determines the angle of bending. This also is why optical mirrors must be front surface mirrors & not the common back surface mirrors as in vanitys. I don't understand. If I flash a light on a tangent it will bend toward the normal line as the site I linked said. This is why I asked the question: which way would a perpendicular light bend since it's, apparently, already travelling the normal line. Josephine
Turtle Posted April 22, 2005 Report Posted April 22, 2005 ___Good point on the tide factor. I don't know how science handles that, but in property that is coastal the measurement is usually 'Mean High Tide' & established through measurement records. Up the coast of Washington, some beach areas have accrued & there is large dispute whether it belongs to coast property owners, the County, or the State. Further, since it seems sea levels are rising, what happens then?___I often listen to the local airtraffic control tower & when the contact incoming planes they give the airports altitude & noticed it changed! I finally realized the planes altimiters are really barometers & they need to 'zero' the onboard altimeter to the barometric reading at ground for the airport.___I wonder how this all relates to how they callibrate the GPS system?___Back to the light beam; I neglected to read the link at first...ooopppss. Anyway, I think I see your point now, almost like the light beam is deciding something then? Maybe is has to do with the crystalline structure of glass. Also, it may bend so as to form a halo, ie. bending equally in a ring? Just some thoughts. ;)
Guest liliangrn Posted April 22, 2005 Report Posted April 22, 2005 I wouldn't have a clue on the light thing ;) . I guess still water would be a better example than glass because you wouldn't have the glass composition to worry about. But you are probably right that it bends somehow. If you were looking at it on an angle it would probably appear bent anyway. There we go I solved it. LOL Interesting facts on the tide stuff aswell. It affects more people than surfers and us girls with PMS. Lol ;) Thanks Turtle
Qfwfq Posted April 22, 2005 Report Posted April 22, 2005 wherein it is often claimed they have a terminal velocity of under 200mph. In point of fact, the USAF in the fiftys hauled a guy up to 100,000 feet on a ballon & then he jumped off & before opening his chute he broke the sound barrier!TV is an aerodynamic issue, the condition is air friction compensating weight. In a sense it means the air friction reduces g to zero. Obviously it depends on altidude so it decreases as you come down fro 100,000 ft, the speed of sound also varies with density, that guy must have reached a great speed while high which then became supersonic bfore he had slowed down enough. I hope his chute withstood the stress!!! P. S. ah, yes, I meant to say, a skydiver will fall a lot slower with arms and legs spread horizontally than when in an upright position, attention-style.
Qfwfq Posted April 22, 2005 Report Posted April 22, 2005 Light will bend inside glass when the incident ray is perpendicular to the surface.QUOTE]No, not when perpendicular. The rule, using angles between the light and the normal to the surface, is that the ratio between the sines of the two angles is given by the ratio between the indices of refraction. Work it out, for when the incoming angle is zero.
Guest liliangrn Posted April 23, 2005 Report Posted April 23, 2005 Just to make a correction on my previous statement: Light has no inertial mass. That is a KNOWN fact supported by agazillion empirical tests. This is a wave effect. The speed of light itself is medium dependent.The constant "c" is spoken of as "the speed of light in vacuo". Butactually the fact that light moves at c in the vacuum is really only aside effect of what c really means. It is fundamentally the limitingspeed at which *information* can move from one point to another inobservable spacer. Light, having no inertial mass therefore moves atthis maximum possible speed. (another fallacy is that nothing movesfaster than light. In fact some stuff can, as long as you can't see ithappen on principle)*Now, in a transparent medium such as air, water or glass, the speed ofinformation itself is less.** That is, c itself is less. Light *still*moves at the speed of information *in that medium*. Then the wave natureof the light produces that well known effect of refractive bending asthe waves have to close up to retain their correct energy at the newvalue of c. You do not of course see this shortening of wavelength, because youcannot actually see light. What you see is an image of a light source,which includes a scattering medium, so we can see objects, but lightitself is invisible The speed is still c. The shorter the wavelengths the longerlight takes to travel the same path. If you could walk along the shorterwave lengths it would be a much longer path than walking along thelonger wave lengths (If you were travelling at a constant rate alongboth paths from point A to Point B. A to B would be a straight line). The so called speeding up and slowing of lightexperiments of late do not apply to the actual light waves themselves,but to what is known as their "group velocity" which is related to theirphase. Say you have a long wave packet whose peak is near the front.Now if you can make that peak move to the back of the packet, it looksas if the light has slowed down if all you are looking at is the peak. It has to do also with the density of the medium they are passing the light through as well. The article stated that the experiment could only be done at near absolute zero.The atoms they are using as a medium are so dense at such a temperature that light waves would be naturallyslower to begin with. Add to that the 'group velocity' and voila, youcan appear to stop light all together for the breifest of moments. Similarly, if you have a wave packet with the peak towards the back andmove it forward, (I'm not too sure how they actually do this, but thisis actually how it works), again if you are only reading the peak, itlooks as if you've made light go faster than c, whereas in fact youhaven't. *Galaxies at about two billion light years and further beyond the Hubblelimit move faster than light. Now I'm leaving!
Kirk Gregory Czuhai Posted May 1, 2005 Report Posted May 1, 2005 Just to make a correction on my previous statement: *Galaxies at about two billion light years and further beyond the Hubblelimit move faster than light. Now I'm leaving!Well, well.. :circle: well i am not going to debate that now ... :shrug: but if you want to make something move faster than the speed of light, point a smallflashlight at one edge of the full moon and scan it back and forth across the moon's surface from the earth from one edge to the oppositie's back and forth fairly quickly.you will be making a paths of photons in a couple of seconds on the moon spreading themfaster than the speed of light! the refration of light ocurring as light travels from say air to water or bounces aroundin a diamond ring (a fancy piece of coal! [carbon]) obeys: Snell's law,---------------> n1*sin(theta2)=n2*sin(theta1) with n2>n1 the n's are called the refractive indicies of the medium and (medium 1,air) and generally are the ratios of the speed of light in the medium divided by the speed of light in air at STP. (medium 2, light speed less than air's) in elementary physics courses snell's law is just accepted as fact but if youwould like a classical physics proof of it treating light as an electromagnetic wavesee Jacksons text, "Classical Electodynamics". Now for the case of "tired" light, i.e. moving "up" through a gravitational field, this is thesame as a de-acceleration due to the equivalence principle of gravitational physics whichhas been experimentally verified mucho! Now since photons only exist and travel at the speed of light in the medium they are in,the only way they could lose energy E=hf would be for them to lower their frequency which since v=wavelenth*frequency for any wave c=wavelenth*frequency of the light andthus the light become more "red" lower in frequency and its wavelength increases to keep the c constant. peace and love,and,love and peace,(kirk) kirk gregory czuhai LOVES ! p.s.the astute reader will see upon reflection upon Snell's law why the lakes and pools lookshallower to the eye than they really are and also,that there exist a criticle angle of incidence theta,c for rays from medium 2 such thatall rays are refracted/reflected BACK into medium 2! Such is the Stuff of what opticalcable is all about!!!!
Damo2600 Posted May 1, 2005 Report Posted May 1, 2005 I am merely an amatuer (so forgive me) but most of this post appears to be physics 'chinese' to me. The torch experiment made no sense to me. If I shake a flash light the photons still move at c. No? "Now since photons only exist and travel at the speed of light in the medium they are in,the only way they could lose energy E=hf would be for them to lower their frequency which since v=wavelenth*frequency for any wave c=wavelenth*frequency of the light andthus the light become more "red" lower in frequency and its wavelength increases to keep the c constant." You didn't explain why the wavelength, rather than the frequency, couldn't change. It would make a lot more sense to me that if the wavelengths of light are shorter. So the light leaving the pool would revert to the air medium wave length. So the light leaving the water from a shorter wave length to a longer wave length would not affect frequency. The fact that light is bent suggests to me that the pool is shorter than it is. So this is where you get a change in velocity of light by stating that the frquency changes and not the wavelength. If the frequency changes and not the wave length that means that light changes velocity. You can't just say that light can't change wave length without stating why. I will have to look into this... Damien
Damo2600 Posted May 1, 2005 Report Posted May 1, 2005 Hey guys I'm back, The wavelength of light in water does change. The wave length can be calculated thus: Wavelength of light in water = wavelength of light in vacuo / n Where n equals the refractive index of water. The following site describes the Refractive Index of water in exceptional degree. http://www.philiplaven.com/p20.html This site shows how a microscope uses shorter wavelengths to see an object upclose by refracting light. em-outreach.ucsd.edu/web-course/Sec-I.A/Sec-I.A.html - This site explains in detail the different frequency of elctro magnetic rays and the ones that are dangerous for you (I've thrown this in for interest) http://micro.magnet.fsu.edu/optics/lightandcolor/electromagnetic.htmlhttp://micro.magnet.fsu.edu/optics/lightandcolor/electromagnetic.html I couldn't find a site, YET, which directly states what I am trying to show. The pool shows the bottom of the pool as being closer than it is. The microscope site explains that a shorter wavelength will make an object appear closer than it is. This can only be achieved by refaction as in the water case. The case is not closed however I must seek out a more effective internet site that explains this case better. I do feel the case is almost closed however. Damien
Tormod Posted May 1, 2005 Report Posted May 1, 2005 I posted a refractive index link in one of your other threads. I am closing this thread as there are now at least three threads about the speed of light.
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