NOF Posted January 20, 2011 Report Posted January 20, 2011 hi. i need to find the maximum possible amount of PbI2, that Created in reaction between 0.3 mol Pb(NO3)2 to 0.2mol KI here is 4 answers Options: A)0.1 mol B)0.15mol C)0.3 mol D)0.5 mol thanks for help. Quote
Qfwfq Posted January 20, 2011 Report Posted January 20, 2011 Well, it is really not difficult. You know that neither Pb nor I can appear out of nothing, and the numbers in the formulae tell you how many moles of each element are in each mole of the compounds. Does this help? Quote
NOF Posted January 20, 2011 Author Report Posted January 20, 2011 Well, it is really not difficult. You know that neither Pb nor I can appear out of nothing, and the numbers in the formulae tell you how many moles of each element are in each mole of the compounds. Does this help? well can you tell me what formula u need to use.i have no problem, to find the Mm and m. BUT i am not sure what formula to use. thank you. Quote
Qfwfq Posted January 21, 2011 Report Posted January 21, 2011 what formula u need to useI meant the formulae that you wrote. Using the tag, let's write the whole, balanced reaction as follows: [ce]xPb(NO3)2 + yKI -> zPbI2[/ce] I suppose you already understand how the reaction needs to be balanced, once you figure out x, y and z it tells you that for each z moles of [ce]PbI2[/ce] you need at least x moles of [ce]Pb(NO3)2[/ce] and at least y of [ce]KI[/ce]. Quote
NOF Posted January 21, 2011 Author Report Posted January 21, 2011 I meant the formulae that you wrote. Using the tag, let's write the whole, balanced reaction as follows: [ce]xPb(NO3)2 + yKI -> zPbI2[/ce] I suppose you already understand how the reaction needs to be balanced, once you figure out x, y and z it tells you that for each z moles of [ce]PbI2[/ce] you need at least x moles of [ce]Pb(NO3)2[/ce] and at least y of [ce]KI[/ce]. ok thank you :) Quote
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