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Posted

The answer is 288.

 

If you had parenthesis around the 2(9+3) it would be two, but since you don't, it's 288.

 

Algebraic proof.

 

x/y(z+w) = (x(z+w))/y = x * 1/y * (z+w) = xz/y + xw/y

 

=/= x/(yz + yw) <-- wrong.

 

Parenthesis are good.

Posted

please, someone smart help these fools to understand that it's 2.

 

Use easy to understand words though, they're not the brightest.

 

 

There are screenshots of google, 2 different graphing calculators, and wolframalpha all showing the answer as 288.

 

Those programs use a proper method of evaluating basic order of operations.

 

The problem, as written, is 288.

 

Edit: A Matlab screenshot of 288 was just posted as well lmao.

Posted

Remember in Algebra 1 when you would do some math problems during class and something like this would come up. Half the class knew how to put it in the calc and the other half just put it in like it says. The teacher very clearly explained to you that you have to put things in parenthesis for the Calculator to understand them. Calculators, including the one that Google and Wolf use, are only as smart as the person using it.

 

(48)/(2(9+3)) = 2

 

Call me when you finish intro to mathematics.

Posted

Remember in Algebra 1 when you would do some math problems during class and something like this would come up. Half the class knew how to put it in the calc and the other half just put it in like it says. The teacher very clearly explained to you that you have to put things in parenthesis for the Calculator to understand them. Calculators, including the one that Google and Wolf use, are only as smart as the person using it.

 

(48)/(2(9+3)) = 2

 

Call me when you finish intro to mathematics.

 

I'm a third year electrical engineering student. You do realize the way you just wrote the problem changes it entirely correct?

 

Good.

 

Use that knowledge. For good or evil. The choice is yours.

Posted

48÷2(9+3) = ????

The answer depends on the precedence of the calculator’s (human, electronic, or whatever) operations.

 

Most calculators have order of precedence (using the usual operator symbols):

() :parenthesis;

*,/ :multiplication or division;

+,- :addition or subtraction;

left to right.

In which case the given expression (rewritten to use the usual explicit operator symbols) evaluates as follows:

48/2*(9+3)

48/2*12

24*12

288

 

If we use this order of precedence: (); *; /; +,- ; left to right. (or ();*,/;+,-; right to left)

The expression evaluates:

48/2*(9+3)

48/2*12

48/24

2

 

Operation precedence, like the actual glyphs used to write arithmetic expressions, is merely a convention – there’s no unqualified right-or-wrong answer to this question.

 

:Exclamati

MISC, tarheelsrule44, Sigh, 288 – you need to familiarize yourselves with hypography’s site rules. Don’t use insulting language, and post in full sentences, not twitter-esque blurbs.

Posted

The answer depends on the precedence of the calculator’s (human, electronic, or whatever) operations.

 

Most calculators have order of precedence (using the usual operator symbols):

() :parenthesis;

*,/ :multiplication or division;

+,- :addition or subtraction;

left to right.

In which case the given expression (rewritten to use the usual explicit operator symbols) evaluates as follows:

48/2*(9+3)

48/2*12

24*12

288

 

Just calculators? I recognize this as the standard precedence I learned in school. It's what we were taught is the 'right' way to do it and it's the order that has been consistent throughout my math texts.

 

If we use this order of precedence: (); *; /; +,- ; left to right. (or ();*,/;+,-; right to left)

The expression evaluates:

48/2*(9+3)

48/2*12

48/24

2

 

Operation precedence, like the actual glyphs used to write arithmetic expressions, is merely a convention – there’s no unqualified right-or-wrong answer to this question.

 

 

When would it be right to use these other orders of precedence? If I ever used them in the past my teacher marked my paper wrong. Is precedence in mathematics really ambiguous?

Posted

Use easy to understand words though

 

Leaving out the rude part (hint ;-) ) If CraigD's answer is too long the thing is in one line:

 

[math]

48/2(9+3)=48/2 \cdot (9+3)= 288 \neq 48/(2(9+3))=48/(2\cdot(9+3))=2

[/math]

Posted

It's my understanding that when presenting a problem to solve, you give it in the simplest form.

 

When I read 48/2(9+3), I see 48 in the numerator and 2(9+3) in the denominator.

 

If it were meant to be (48/2)(9+3) why would it not be written 24(9+3)?

 

For instance, I would solve

 

a/x(y+z)

 

The only way to simplify that, in my mind is:

 

a/(xy+xz)

 

So, punch in the numbers now:

a=48, x=2, y=9, and z=3

 

Now you have:

 

48/(2(9)+2(3))

 

48/(18+6)

 

48/24

 

2

 

The other way would have to be:

 

a/x(y+z)

 

(a/x)y+(a/x)z

 

but a/x is not a single variable. Unless it's written as 24. The division sign (/) signifies a fraction in which 2(9+3) is in the denominator as a whole.

 

Maybe I'm over analyzing but I feel like once you get past a certain math class (algebra 1 or 2) you no longer see division symbols, but you see fractions.

 

As I continue to write, I can see more and more how to get 288. Especially if you view 48/2 as a single variable, but i feel this is wrong.

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