Does This Make Sense

[MattEvans]

1 GeV/c2 = 1.783×10−27 kg

 

possibility the Higgs may exist with a mass around 125 GeV/c2

 

Multiply the photon's frequency by Planck's constant.

 

Planck's constant is [ 6.626 x 10^-34 Joule-second ] (rounded)

 

E, j = m, kg * c^2, m/s

 

E = 1.783*10^-27 * 125 * 299792458^2

 

Joules in Higgs Boson = 2.0031006 * 10^-8

 

photon in matter 1/299792458 sec frequency

 

Photonic energy per photon in joules = 5.92*10^-20

 

Photons in Higgs Boson 338361587837

 

Anyone know the volume for a photonic density?

[CraigD]

Welcome to hypography, Matt! :) My complements on an interesting first post. :thumbs_up

 

1 GeV/c2 = 1.783×10−27 kg

 

possibility the Higgs may exist with a mass around 125 GeV/c2

 

Multiply the photon's frequency by Planck's constant.

 

Planck's constant is [ 6.626 x 10^-34 Joule-second ] (rounded)

 

E, j = m, kg * c^2, m/s

 

E = 1.783*10^-27 * 125 * 299792458^2

 

Joules in Higgs Boson = 2.0031006 * 10^-8

Everything up to here seems to me to agree with the usual references, and have correct units.

 

photon in matter 1/299792458 sec frequency

I’m uncertain what you mean by “photon in matter”. Photons and other elementary bosons don’t, in conventional QED terms, exist in fermions, so can’t be “in matter” in the strictest sense of the word. We speak of photons as being “in matter” when they are passing through a transparent solid such a block of glass, but more accurately, semiclassically, photons in this state are “between and interacting with matter” in a way not fundamentally different than when they pass through a gas, including the very diffuse gas we think of as “ordinary vacuum”.

 

Although in principle a photon can have an arbitrarily low frequency, as low as [imath]\frac{1}{299792458 \,\text{s}}[/imath], with an energy of about [imath]2.2\times10^{-42}\,\text{J}[/imath] I don’t believe one so low could be detected. I believe you meant to write [imath]\frac{299792458}{1 \,\text{s}}[/imath], or about [imath]3\times10^8 \,\text{s}^{-1}[/imath] or 300 MHz. This is about the UHF radio frequency. A visible orange-yellow photon has a frequency of [imath]6\times10^{14} \,\text{s}^{-1}[/imath] or 6 THz.

 

Photonic energy per photon in joules = 5.92*10^-20

 

Photons in Higgs Boson 338361587837

Your calculation looks correct, but the still-unconfirmed Higgs boson doesn’t contain, nor is it made of, photons. It’s hypothesized to be an elementary boson, in the same family of particles as the photon.

 

Anyone know the volume for a photonic density?

Bosons follow Bose-Einstein statistics (that’s why their named bosons) so there is no limit to their density – how many, of how great a total energy of them, can be contained in a given unit volume.

 

The density [imath]D[/imath] of photons of a particular monochrome beam of EM radiation can be calculated by (if I haven’t erred in my formulating)

[math]D = \frac{h v}{c} I[/math]

where [imath]h[/imath] is the Planck constant, [imath]v[/imath] the photons’ frequency, [imath]c[/imath] the speed of light, and [imath]I[/imath] the beam’s irradiance.

 

Ignoring gravity, In principle, given any EM radiation source and a sufficiently large lens that can refract it, there’s no limit to the irradiance that can be concentrated on a given macroscopic target area, so no limit to the density of photons that can be concentrated in a given macroscopic volume.

 

Including gravity, I think it’s in principle possible to pack photons so densely a black hole occurs, putting an upper limit on the maximum irradiance that a beam of EM radiation of a particular spectrum. I expect this is a pretty huge value, however, the calculating of which is left as an exercise for the reader. :)