Aethelwulf Posted October 19, 2013 Author Report Posted October 19, 2013 (edited) If we solve for the temperature of the system, we do find a nice equation [math]T = \sqrt[4]{\frac{j^{*} (1 + z)^2}{\epsilon(\lambda) \sigma}}[/math] This appears actually like an important equation. There are in fact strong similarities between this model of temperature with an equation used to calculate radiation flux, solved for temperature that equation looks like [math]T = \sqrt[4]{\frac{(1 - a)S}{4 \epsilon \sigma}}[/math] The [math]S[/math] calculated a flux density, in our equation derived, it is also a type of flux, an emissive power to be precise. The factor [math](1-a)[/math] is dimensionless, it just calculates the reflective properties of the Earth, in our equation, our term [math](1+z)[/math] is also dimensionless. The denominator is pretty much the same as well, so the similarities are very strong. Edited October 19, 2013 by Aethelwulf Quote
Aethelwulf Posted October 19, 2013 Author Report Posted October 19, 2013 (edited) It is actually, naturally occurrent to multiply our temperature equation by the constant [math]k[/math] which resides as an electromagnetic feature of the situation and acts as a bridge between micro to macro-systems. [math]E = k\sqrt[4]{\frac{j^{*} (1 + z)^2}{\epsilon(\lambda) \sigma}}[/math] What we have in return is an energy again, which appears when calculating the average translational kinetic energy. This energy is part of no doubt, a Hamiltonian of the system, since each charge is responsible for the total luminosity output, described by the flux density. Edited October 19, 2013 by Aethelwulf Quote
Aethelwulf Posted October 19, 2013 Author Report Posted October 19, 2013 (edited) 'removed' Edited October 20, 2013 by Aethelwulf Quote
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