Masterov Posted April 18, 2016 Report Share Posted April 18, 2016 (edited) The relativistic mass increase is a consequence ofthe erroneous assumption thatthe Coulomb force is absolute anddoes not depend on speed .We are told that the Coulomb force: \(F = qE\) This give a false statement thatthe energy of a relativistic particlegrows in proportion to the difference ofthe accelerating field potentials: \(W = mv^2/2 = -qU\)However, since the rate of relativistic particlesin the accelerator ceases to grow,but (according to this formula) the energycontinues to grow - from here and get thatthe speed increases mass.We correct this errorCoulomb force so depends on the speed: \(F = qE(1-\frac{v^2}{c^2})\)Integrating this expression , we obtain: \(W = \frac{mv^2}{2} = (1 - e^{-2qU/mc^2})\frac{mc^2}{2}\) VerifyWe differentiate the last expression:\(1-\frac{v^2}{c^2} = e^{-2qU/mc^2}\)\(ln(1-\frac{v^2}{c^2}) = -\frac{2qU}{mc^2}\)\(\frac{2v/c^2}{1-v^2/c^2}dv = -\frac{2q}{mc^2}dU\)\(mv\ dv = -qdU(1-\frac{v^2}{c^2})\)\(m\frac{dx}{dt}dv = -qdU(1-\frac{v^2}{c^2})\)\(m\frac{dv}{dt} = -q\frac{dU}{dx}(1-\frac{v^2}{c^2})\)\(ma = qE(1-\frac{v^2}{c^2})\)\(F = qE(1-\frac{v^2}{c^2})\) Does my formula the agreement with the results of experiments?From my formula that the kinetic energy of the electrons inthe accelerator may not exceed 255KeV \( = mc^2/2\) And it confirms any physics reference book,where there is a section " X-rays". Please note that : for any difference potential energy X-ray photons does not exceed value 255KeV \( = m_ec^2/2\) (On the X-ray tube or electron accelerator) Energy did measured using calorimeters.And for electrons and for protons. The maximum kinetic energy of the proton in the acceleratornever exceeded value 470MeV \( = m_pc^2/2\)Large values of energy, about which report Physics to us, exist only on paper.To verify this , I propose to conduct a simple experiment. Scheme of experiment I propose below. Edited April 18, 2016 by Masterov Quote Link to comment Share on other sites More sharing options...
Masterov Posted April 18, 2016 Author Report Share Posted April 18, 2016 (edited) Scheme of experimentThe experiment: To determine the dependence of the kinetic energy of relativistic electrons on the difference of the accelerating field potentials. The experiment to do measure: the anode current,the difference of the accelerating field potentialsand the temperature of anode. Experimental results should be a two-dimensional table in which the cells - the target temperature. Two dimensional coordinates of this table: the beam current and the difference between the potential of the accelerating field. This table will determine which of the approximation is more suitable for the prediction of the experiment. Einstein offers the approximation: \(W = \frac{mv^2}{2}\sim U\) My approximation: \(W = \frac{mv^2}{2}\sim 1 - e^{-U/255}\)If my approximation would be more accurate:Special Theory of Relativity will cease to be a scientific theory. Edited April 18, 2016 by Masterov Quote Link to comment Share on other sites More sharing options...
Masterov Posted April 19, 2016 Author Report Share Posted April 19, 2016 (edited) To which some quick and easy algebra give the answer “[math]\frac{1+\sqrt{5}}{2}[/math]”.My english is poor, very poor.I do'nt andestend text, butI experienced the emotionswhen I saw the expression of [math]\frac{1+\sqrt{5}}{2}[/math] I've seen it already! I tell... If you observe distant galaxies,which moves on a parallel course with the Earth, then... You measured visual speed [math]v'[/math] of the galaxy, which is growing.If [math]v'>\frac{2c}{1+\sqrt{5}}[/math] - galaxy disappeared. You do'nt see galaxy, if visual speed of it [math]>\frac{2c}{1+\sqrt{5}}\approx 185 281 929 m/c[/math] Edited April 19, 2016 by Masterov Quote Link to comment Share on other sites More sharing options...
Masterov Posted April 20, 2016 Author Report Share Posted April 20, 2016 My English is very poor.I ask you to write short sentences, so I can understand you.Plees. My ansver: I do not put into question the Michelson-Morley experiment (speed of light is constant).I do not preach the existence of the aether.I show that the problem that Einstein decided to have more than one solution. Three of Einstein's mistakes (Scheme of experiment) \(v\) - real speed of the observer\(v'\) - visual speed of the clock relative to the observer. \(\frac{v'}{v}=-(1-\frac{v'^2}{c^2})\)\(v=-\frac{v'}{1-v'^2/c^2}\)\(v'=-\frac{2v}{\sqrt{1+4v^2/c^2}+1}\) If real speed \(v=c\), then \(v'=\frac{2c}{\sqrt{5}+1}\) \(x'=v't\)\(x=vt\) \(\vec v(t) = \vec v_o+\int_o^t\vec a(t)dt\)\(\vec r(t) = \vec r_o+\int_o^t\vec v(t)dt\) acceleration is the absolute Quote Link to comment Share on other sites More sharing options...
jerrygg38 Posted April 24, 2016 Report Share Posted April 24, 2016 In my latest book "The Gravitational Wave and the Dot-Wave theory" particles constantly radiate both mass and charge which forms gravitational waves and electromagnetic waves. When you accelerate a mass, some of the momentum increases the mass in the form of spherical waves and some increases its velocity which is a linear component. We then get a formula for increasing mass with velocity and increasing inertia with velocity. The mass increase tends to level off as the additional energy radiates away. the formula for gravitational mass is Mg = Mo /(1-(v/C)2)0.5 This is Einstein's formula which is correct for the gravitational massThe inertial mass is more the formula is Mi = Mo/(1-(v/C)2) This would be the total equivalent mass/energy of the moving object. As we go back in time toward the big bang, the charges of the proton and electron were much larger. The question is whether when we add energy to an electron or proton, does only the photonic (bipolar energy) increase and the mass/inertial increases or does the photonic energy split and causes the particle's charge to increase as well? Thus do we go back in time to a little after the big bang when the charge Q was much larger? In any event Einjsteins special relativity is a good approximation to the mass increase because it is the root means square of the Doippler Equations. Your thoughts may be basically true,. Quote Link to comment Share on other sites More sharing options...
Masterov Posted April 27, 2016 Author Report Share Posted April 27, 2016 In my latest book "The Gravitational Wave and the Dot-Wave theory" particles constantly radiate both mass and charge which forms gravitational waves and electromagnetic waves. When you accelerate a mass, some of the momentum increases the mass in the form of spherical waves and some increases its velocity which is a linear component. We then get a formula for increasing mass with velocity and increasing inertia with velocity. The mass increase tends to level off as the additional energy radiates away. the formula for gravitational mass is Mg = Mo /(1-(v/C)2)0.5 This is Einstein's formula which is correct for the gravitational massThe inertial mass is more the formula is Mi = Mo/(1-(v/C)2) This would be the total equivalent mass/energy of the moving object. As we go back in time toward the big bang, the charges of the proton and electron were much larger. The question is whether when we add energy to an electron or proton, does only the photonic (bipolar energy) increase and the mass/inertial increases or does the photonic energy split and causes the particle's charge to increase as well? Thus do we go back in time to a little after the big bang when the charge Q was much larger? In any event Einjsteins special relativity is a good approximation to the mass increase because it is the root means square of the Doippler Equations. Your thoughts may be basically true,.Mass is independent by of the speed and are absolute value (together with speed of light). Quote Link to comment Share on other sites More sharing options...
Masterov Posted April 27, 2016 Author Report Share Posted April 27, 2016 The force exerted on the electric charge in the electromagnetic field: \(\vec F=q(\vec E-[\vec r\vec {rot E}]+[\vec v\vec H])(1-v^2/c^2)\) Quote Link to comment Share on other sites More sharing options...
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