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Hello, I will try to explain the topic title to the best of my ability .

 

We shall start by placing three different values in a row . Numbered 1,2 and 3 .

 

 

123

 

 

 

We shall then hide the values and randomly mix up the positions, leaving 3 values but now in unknown position.

 

 

 

XXX

 

 

I shall now offer you the first on the left unknown value .

 

 

 

P1=1/3

 

P2=1/3

 

P3=1/3

 

 

Before I continue, are we all in agreement with the probability stated, that the 1st value on the left has an equal 1/3 chance of being either 1,2 or 3?

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