Sigmar Posted April 29, 2017 Report Posted April 29, 2017 Hey I was wondering if you could balance this equation and show how you balanced itCO + O2 -----> CO2 thanks Quote
JMJones0424 Posted April 29, 2017 Report Posted April 29, 2017 It's not possible, as the right hand of the equation must include enough oxygen atoms to equal those that exist in the left side of the equation. I suspect that you have either provided a false equivalency or have neglected something. It could be the case that 2CO + O2 -> 2CO2 This equation is balanced because there are equal numbers of C atoms and O atoms on either side, namely 2 Carbon atoms and 4 Oxygen atoms. exchemist and Sigmar 2 Quote
JMJones0424 Posted April 29, 2017 Report Posted April 29, 2017 (edited) We've balanced the equation, but why is this equation valid? I don't remember enough about chemistry to know that this is the correct answer. Edited April 29, 2017 by JMJones0424 Quote
exchemist Posted April 29, 2017 Report Posted April 29, 2017 We've balanced the equation, but why is this equation valid? I don't remember enough about chemistry to know that this is the correct answer.Yes it is the equation for the combustion of carbon monoxide. This is what you see in the little blue flames that lick round red-hot coals. JMJones0424 1 Quote
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