Liquid Pressure

[guan721]

Notes:
Water density = 1000 kg/m3
Mercury density = 13600 kg/m3
g = 10 N/kg

Hi all, please help on this questions. The attempt from me
a)
(0.7m)(1000kg/m3)(g) = (h)(13600kg/m3)(g)
h = 0.0514m
h = 5.14cm

Assume h = 5.14cm is based on same surface area between both side of tube, however, for different surface area of tube, the h = 5.14cm have to be adjusted

Let d = diameter of wider tube
Surface area of narrower tube = (1/8 x d) ^2 = 1/64d2
h = 5.14cm, based on (1/64)(d^2)

Surface area of wider tube = (1/2 x d) ^ 2 = 1/4d2
to get the same volume, h of wider tube have to be lesser

h1d1 = h2d2
(5.14cm)(1/64)(d^2) = (h2)(1/4)(d^2)
h2 = 0.32cm


:cool: By refer to the a) calculation, the level dropped from mercury in narrower tube = 5.14cm

c) I have no clue about this question, as I can't confirm the concept I used to solve a) and :cool: whether correct or wrong.

Kindly help, many thanks.

Edited October 15, 2017 by guan721

[Vmedvil]

Notes:

Water density = 1000 kg/m3

Mercury density = 13600 kg/m3

g = 10 N/kg

 

Hi all, please help on this questions. The attempt from me

a)

(0.7m)(1000kg/m3)(g) = (h)(13600kg/m3)(g)

h = 0.0514m

h = 5.14cm

 

Assume h = 5.14cm is based on same surface area between both side of tube, however, for different surface area of tube, the h = 5.14cm have to be adjusted

 

Let d = diameter of wider tube

Surface area of narrower tube = (1/8 x d) ^2 = 1/64d2

h = 5.14cm, based on (1/64)(d^2)

 

Surface area of wider tube = (1/2 x d) ^ 2 = 1/4d2

to get the same volume, h of wider tube have to be lesser

 

h1d1 = h2d2

(5.14cm)(1/64)(d^2) = (h2)(1/4)(d^2)

h2 = 0.32cm

 

 

:cool: By refer to the a) calculation, the level dropped from mercury in narrower tube = 5.14cm

 

c) I have no clue about this question, as I can't confirm the concept I used to solve a) and :cool: whether correct or wrong.

 

Kindly help, many thanks.

 

Looks right to me, i didn't do the numbers but the algebra is correct.