Super Polymath Posted November 10, 2017 Report Share Posted November 10, 2017 Define L now.I mean it's potentially unlimited but you need to set limits like the Planck length or the cosmic radius. Quote Link to comment Share on other sites More sharing options...
Vmedvil Posted November 10, 2017 Report Share Posted November 10, 2017 I mean it's potentially unlimited but you need to set limits like the Planck length or the cosmic radius. Well, read this paper that is still a wrong state value.http://file.scirp.org/Html/14-7501108_33092.htm Quote Link to comment Share on other sites More sharing options...
Super Polymath Posted November 10, 2017 Report Share Posted November 10, 2017 Well, read this paper that is still a wrong state value. http://file.scirp.org/Html/14-7501108_33092.htmL can be whatever it needs to be for your approx survival probability, then. The smaller the better. Quote Link to comment Share on other sites More sharing options...
Vmedvil Posted November 10, 2017 Report Share Posted November 10, 2017 (edited) L can be whatever it needs to be for your approx survival probability, then. The smaller the better. when then L is still not defined which brings us back to define L as L ≠ H which is the Hubble constant. . Edited November 10, 2017 by Vmedvil Quote Link to comment Share on other sites More sharing options...
Super Polymath Posted November 11, 2017 Report Share Posted November 11, 2017 (edited) when then L is still not defined which brings us back to define L as L ≠ [/size]H which is the Hubble constant.[/size] . [/size]L is basically the Mandelbrot set, it requires infinite calculations & is undefinable. Why do you need to fully define how small or large the dimensions of gravity or motion of bodies can get when you know they're neither zero nor infinity. Just treat L as you would any other asymptote. Edited November 11, 2017 by Super Polymath Quote Link to comment Share on other sites More sharing options...
Vmedvil Posted November 11, 2017 Report Share Posted November 11, 2017 (edited) L is basically the Mandelbrot set, it requires infinite calculations & is undefinable. Why do you need to fully define how small or large the dimensions of gravity or motion of bodies can get when you know they're neither zero nor infinity. Just treat L as you would any other asymptote. See, I realize how screwed up that was last night when dubblesiox pointed out that the values didn't match and me only having a E7 for Supergravity. I dunno Unable to visually construct image error meaning I really don't know why that doesn't balance. Edited November 11, 2017 by Vmedvil Quote Link to comment Share on other sites More sharing options...
Vmedvil Posted November 11, 2017 Report Share Posted November 11, 2017 L is basically the Mandelbrot set, it requires infinite calculations & is undefinable. Why do you need to fully define how small or large the dimensions of gravity or motion of bodies can get when you know they're neither zero nor infinity. Just treat L as you would any other asymptote. Yes, it does actually look something like that but now I dunno how to define p/q for Supergravity. If Quote Link to comment Share on other sites More sharing options...
Super Polymath Posted November 11, 2017 Report Share Posted November 11, 2017 Any point where de sitter & anti de sitter space are perpendicular would be your p's & q's. Quote Link to comment Share on other sites More sharing options...
Vmedvil Posted November 11, 2017 Report Share Posted November 11, 2017 (edited) Any point where de sitter & anti de sitter space are perpendicular would be your p's & q's. So, like a D brane then p = 2 , so basically a wormhole passage. This places Dark Energy as Tachyon Radiation. Edited November 11, 2017 by Vmedvil Quote Link to comment Share on other sites More sharing options...
Super Polymath Posted November 11, 2017 Report Share Posted November 11, 2017 (edited) so basically a wormhole passage. No, black holes. They're closed on all sides. A black hole in de sitter space translates to a white hole in anti de sitter space, a black hole in anti de sitter space translates to the dimensions we inhabit. A white hole is a boundless 2.something dimensional sphere with no real boundary. Basically infinite size, it's the inside out of a black hole.http://www.scienceforums.com/topic/30597-the-theory-of-everything/ Edited November 11, 2017 by Super Polymath Quote Link to comment Share on other sites More sharing options...
Super Polymath Posted November 11, 2017 Report Share Posted November 11, 2017 Dark Energy as Tachyon Radiation.Spacetime is always going inward in a black hole, so in a white hole it's always going outward. But this is still very much caused by de sitter & anti de sitter space, two separate collections of infinite parallel universes (black holes & white holes) encasing each other. Quote Link to comment Share on other sites More sharing options...
Super Polymath Posted November 11, 2017 Report Share Posted November 11, 2017 So reality is a 5 dimensional hypersphere. A snake eating its own tail. Mass & energy being fluctuations in the density mediums of two realities with opposite temporal linearities as the snake eats it's own tail. This is why there can infinite bodies in motion infinitely beneath the Planck length. Which is why you get Esub(8+n). Quote Link to comment Share on other sites More sharing options...
Vmedvil Posted November 11, 2017 Report Share Posted November 11, 2017 So reality is a 5 dimensional hypersphere. A snake eating its own tail. Mass & energy being fluctuations in the density mediums of two realities with opposite temporal linearities as the snake eats it's own tail. This is why there can infinite bodies in motion infinitely beneath the Planck length. Which is why you get Esub(8+n). Ya sorry, Super Polymath this is where I draw the line I think Dubblesoix was right, this is generating anomalies in my equations because of DE being Tachyon Radiation and white and black holes The Correct form is. [math] Planck-Curvature = \frac{2}{3} <\psi|R_{ij}|\psi> \pi (\sqrt \frac{1}{L_p^2})^3 [/math] Then [math] \Delta <E> = \frac{C^4}{12 G } \int \Delta <R_{ij}> (\sqrt \frac{1}{L_p^2})^3 = \frac{C^4}{12 G } \int <\psi|(R_{ij} - <\psi |R_{ij}| \psi>)|\psi> (\sqrt \frac{1}{L_p^2})^3 [/math] [math] \sqrt \frac{1} { t_p^2 C^2}= \sqrt \frac{1} { L_p^2} =\sqrt \frac{1}{ E_8 E_8} [/math] [math] t_p^2= O^2 [/math][math] c^2 = P^2[/math] That Transformation to E has to be wrong. [math] Planck-Curvature = \frac{2}{3} <\psi|R_{ij}|\psi> \pi (\sqrt \frac{E}{L_p^2})^3 [/math] Then [math] \Delta <E> = \frac{C^4}{12 G } \int \Delta <R_{ij}> (\sqrt \frac{E}{L_p^2})^3 = \frac{C^4}{12 G } \int <\psi|(R_{ij} - <\psi |R_{ij}| \psi>)|\psi> (\sqrt \frac{E}{L_p^2})^3 [/math] [math] \sqrt \frac{E} { t_p^2 C^2}= \sqrt \frac{E} { L_p^2} =\sqrt \frac{E}{ E_8 E_8} [/math] [math] t_p^2= O^2 [/math][math] c^2 = P^2[/math] Quote Link to comment Share on other sites More sharing options...
Super Polymath Posted November 11, 2017 Report Share Posted November 11, 2017 It's not tachyon radiation unless you're beneath the Planck length where it's still not tachyon radiation because time has contracted enough to transform the speed of light just as it transformed the Planck length. It's conformal, this has to do with fractal dimensionality (Mandelbrot set) not anti de sitter space. Quote Link to comment Share on other sites More sharing options...
Vmedvil Posted November 11, 2017 Report Share Posted November 11, 2017 (edited) It's not tachyon radiation unless you're beneath the Planck length where it's still not tachyon radiation because time has contracted enough to transform the speed of light just as it transformed the Planck length. It's conformal, this has to do with fractal dimensionality (Mandelbrot set) not anti de sitter space. So, what you are saying is beyond Contracting Space and dilating Time there is a C Relativity which causes C to increase relative to time increase and decrease in space which makes it "Non Tachyonic" domain but still above C, but this generates Cherekov radiation due to the Higgs mechanism being Dark Energy, but the problem with that is it breaks conservation of Energy-Momentum I have had this discussion before the Universe would be losing energy-mass. Edited November 11, 2017 by Vmedvil Quote Link to comment Share on other sites More sharing options...
Super Polymath Posted November 11, 2017 Report Share Posted November 11, 2017 (edited) So, what you are saying is beyond Contracting Space and dilating Time there is a C Relativity which causes C to increase relative to time increase and decrease in space which makes it "Non Tachyonic" domain but still above C, but this generates Cherekov radiation due to the Higgs mechanism being Dark Energy, but the problem with that is it breaks conservation of Energy-Momentum I have had this discussion before the Universe would be losing energy-mass. No, it would dispersing energy across a boundless plane, merely decreasing the density medium of reality like the vacuum radiation in-between galactic superclusters, & gaining the energy contained within parallel universes as they combine with it as black hole mergers in anti-desitter space. Edited November 11, 2017 by Super Polymath Quote Link to comment Share on other sites More sharing options...
Vmedvil Posted November 11, 2017 Report Share Posted November 11, 2017 (edited) No, it would dispersing energy across a boundless plane, merely decreasing the density medium of reality like the vacuum radiation in-between galactic superclusters, & gaining the energy contained within parallel universes as they combine with it as black hole mergers in anti-desitter space. So then it would be a Quantum entanglement like system. Edited November 11, 2017 by Vmedvil Quote Link to comment Share on other sites More sharing options...
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