phamtiendung135 Posted May 6, 2018 Report Posted May 6, 2018 (edited) Electric fields, magnetic fields ... exist in two opposing states:· charge (+) and charge (-)· north pole and south poleGravitational field has something wrong because it only has gravity without repulsive forces. Let us now assume that the "gravitational constant G" is not invariant by distance. It can take negative values, positive and zero. · When ( G < 0 ), it will have gravity· When ( G > 0 ), there will be thrust· When ( G = 0 ), there is no force At the point where G = 0 is called the the equilibrium position. There are two types of equilibrium position: sustainable ( R2) and non-sustainable ( R1 , R3). · At R2: If the moving object moves away from M, it is pulled in. If it goes in the direction of movement near the M, it will be pushed away. As a result, it simple harmonic motion around the equilibrium position R2. The amplitude of this simple harmonic oscillation can be very large.· At R1 and R3, if the object deviates from the equilibrium position, it will be pulled in or ejected. The connection of objects in galaxies is similar to the bonding of atoms in the metal network. Thus, galaxies can exist in all different shapes. In the distance from M to R1 is equal to L1. G<0 and R1 are said to be boundaries of Oort cloud because matter outside of R1 would be pushed out of the solar system. So: R1 = 1.ly Is gravitational constant a constant? All experiments to find this constant are done at very small distances. This is a shortcoming in science. At great distances, humans rely on the motions of planets to find G. The law of Kepler 3 shows us that G is not a constant: Recently, Pioneer 10 and Pioneer 11(Pioneer anomaly) show that G increases with distance. Absolute values of G tend to increase with distance. G decreases to zero and changes the sign (negative, positive) when passing through the equilibrium point. (See the illustration below). The gravitational constant G is forced to increase to serve the following problem: It is the energy conservation of gravitational waves. If : L1 = L2 = L3 =... = Ln, then G is forced to rise too fast. This is unreasonable. Therefore, L must also increase along with G. I have an assumption that: Ln+1 = K . Ln with K > 1. I'm leaning toward the plan :K = 3“This is just a guess, because most of the objects at distance 3ly have a direction of motion away from the solar system”As G increases with distance, all gravitational calculations will no longer be valid. Gravity is much bigger than what we think. This is dark matter. Gravitational field is not only gravity but also repulsive force. This is dark energy. Edited May 6, 2018 by phamtiendung135 Quote
Vmedvil2 Posted June 28, 2018 Report Posted June 28, 2018 (edited) Yes, the gravitational constant is constant, what non sense little g is the one that changes based on the mass of the object and distance Big G never changes and is the universal gravitational constant which Dark Matter still has gravity which is nothing close to a solution saying it is not constant..... NEXT! What this forum has been missing is someone to Peer Review this stuff, and I say to this post, Failed! Edited June 28, 2018 by VictorMedvil Quote
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