Vmedvil2 Posted July 9, 2018 Report Posted July 9, 2018 (edited) The gravitons are invisible black holes located all about the volume of the inverse of the spherical coordinates located at the conic sections of the triangles of the 60th iteration of a 3D 9-folded angle (at 3 90 degree & 6 45 degree angles between those 90 degree angles [sine & cosine]) version of a square composed of 4 koch snowflake/antisnowflake equilateral triangles whose triangle tops (the point at the top of the triangle) are touching in the middle of the square of positively charged photons (phonon excitations) in an ideally redshifted vacuum medium. I see you have started to do differential geometry, I have never taken the geometric sequences that far before, but I believe you. You are talking about the 9th angle of the Yau Manifold or dimension 9. Once, again I have speculated before that Photons along with all bosons are nothing more that singularities with different properties. That could be said for any bosonic wave-particle. Edited July 9, 2018 by VictorMedvil Quote
Super Polymath Posted July 9, 2018 Report Posted July 9, 2018 Those are the superluminal gravitons in which the one direction where positive charge of a proton is congruent with the direction in which the proton is going propagates between entangled states of other protons with perpendicular trajectories, in their respective microverses the black holes are expanding away from one another in the photon aether faster than light in the positively charged photon. Quote
Super Polymath Posted July 10, 2018 Report Posted July 10, 2018 I see you have started to do differential geometry, I have never taken the geometric sequences that far before, but I believe you. You are talking about the 9th angle of the Yau Manifold or dimension 9. Once, again I have speculated before that Photons along with all bosons are nothing more that singularities with different properties. That could be said for any bosonic wave-particle.A collection of googols of singularities per "individual" photon Quote
Super Polymath Posted July 10, 2018 Report Posted July 10, 2018 (edited) An anti proton only has one singularity in the sub-planck middle of it's quasar Edited July 10, 2018 by Super Polymath Quote
Vmedvil2 Posted July 10, 2018 Report Posted July 10, 2018 (edited) Those are the superluminal gravitons in which the one direction where positive charge of a proton is congruent with the direction in which the proton is going propagates between entangled states of other protons with perpendicular trajectories, in their respective microverses the black holes are expanding away from one another in the photon aether faster than light in the positively charged photon.For temperature to escape a Singularity there would need to be superluminal gravitons that also can travel between different brane on the multiverse, it is currently unknown the interaction of the graviton besides that they can cause photons to escape BH tho. Edited July 10, 2018 by VictorMedvil Quote
Super Polymath Posted July 10, 2018 Report Posted July 10, 2018 That's why the kerr metric applies only to the anti proton Quote
Vmedvil2 Posted July 10, 2018 Report Posted July 10, 2018 (edited) That's why the kerr metric applies only to the anti protonYour theory subjects every particle to being a Singularity of some sort but the Kerr metric would apply to any BH that is spinning in actuality. If an anti-proton is a singularity then the photon sphere would apply to its electron's orbital too. Edited July 10, 2018 by VictorMedvil Quote
Super Polymath Posted July 10, 2018 Report Posted July 10, 2018 (edited) For temperature to escape a Singularity there would need to be superluminal gravitons that also can travel between different brane on the multiverse, it is currently unknown the interaction of the graviton besides that they can cause photons to escape BH tho.The interaction occurs when those photons phase any entangled state particles that cross the pilot wave (a collective of gravitons within the phonon) Edited July 10, 2018 by Super Polymath Quote
Shustaire Posted July 10, 2018 Report Posted July 10, 2018 (edited) all particle creation comes in pairs. Edited July 10, 2018 by Shustaire Quote
Vmedvil2 Posted July 10, 2018 Report Posted July 10, 2018 (edited) comes in particle creation arises in pairs. The question is what are they pair producing from, there should be no matter or antimatter in a BH due to gravitational stress would rip the particles apart, so the creation of these particles is coming from something else shustaire. Edited July 10, 2018 by VictorMedvil Quote
Shustaire Posted July 10, 2018 Report Posted July 10, 2018 Photons are the gauge boson for temperature, particles can arise from anywhere. The lifetime of that particle depends on two factors the energy level and its decay rate. Temperature is part of the EM spectrum Ie infra red particles pop in and out of existence from a field all the time. It literally occurs all the time anywhere there is sufficient field potential to do so. Quote
Super Polymath Posted July 10, 2018 Report Posted July 10, 2018 The question is what are they pair producing from, there should be no matter or antimatter in a BH due to gravitational stress would rip the particles apart, so the creation of these particles is coming from something else shustaire.Fusion of singularities when the photons collide at their shortest wavelengths to create heavier particles. Quote
Super Polymath Posted July 10, 2018 Report Posted July 10, 2018 (edited) In the photon, these singularities are infinitesimal. They're literally at every point in the redshift photon in an ideal vacuum. They each have tiny little quasars both in the negatively charged photon phase & the positively charged photon phase - as well as in the shortest wavelength, it's neutrally charged phase. The visible spectrum can be - & + but the brightest wavelength is neutral that's where the most particle production occurs. Edited July 10, 2018 by Super Polymath Quote
Shustaire Posted July 10, 2018 Report Posted July 10, 2018 (edited) precisely under QFT this is described using creation and annihilation operators. The entangled state arises from the conservation laws in this case. Yes the transformation describing that does use creation and annihilation processes, but your physics is wrong, we generally attribute that to a pair production on the horizon, not anything to do with the interior. Physics has a milestone to explain not only how the information escapes, but how that information is preserved after it has fallen past the boundary, because the information entanglement becomes destroyed which leads to an information loss Edited July 10, 2018 by Shustaire Quote
Vmedvil2 Posted July 10, 2018 Report Posted July 10, 2018 (edited) Photons are the gauge boson for temperature, particles can arise from anywhere. The lifetime of that particle depends on two factors the energy level and its decay rate. Temperature is part of the EM spectrum Ie infra red particles pop in and out of existence from a field all the time. It literally occurs all the time anywhere there is sufficient field potential to do so. That is true with loss of energy from orbitals of electrons around the nucleus and the electrons sinking to a lower state of excitation around the nucleus but there must be a particle that generates them in a BH due to lack of anything orbiting the BH, some sort of particle must decay into these photons and secondly you are forgetting that photons should not be able to escape the BH. There must be a bridge particle between the raw energy and the photons, something losing kinetic energy, temperature cannot directly just convert itself from inside a gravitational attraction that is the speed of light from temperature, there is some particle that allows them to escape into hawking radiation being a graviton or gravity wave-particle, even Dubbel's equations predict this by the change in wavelength experienced which requires a mediator particle. Edited July 10, 2018 by VictorMedvil Quote
Vmedvil2 Posted July 10, 2018 Report Posted July 10, 2018 (edited) Yes the transformation describing that does use creation and annihilation processes, but your physics is wrong, we generally attribute that to a pair production on the horizon, not anything to do with the interior. Physics has a milestone to explain not only how the information escapes, but how that information is preserved after it has fallen past the boundary, because the information entanglement becomes destroyed which leads to an information loss.Then how does it remove temperature then dubbel without interaction to the interior of the BH. If there is no mediator allowing the exchange. Edited July 10, 2018 by VictorMedvil Quote
Shustaire Posted July 10, 2018 Report Posted July 10, 2018 Why would you beleive it requires other particles to create a photon particle pair? Quote
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