Vmedvil2 Posted October 10, 2019 Report Posted October 10, 2019 (edited) Let's Start with Einstein's Field Equation General Form. Now in order to merge this with Quantum Mechanics via space coordinates we must solve the equation for Radius® which is -2(8πGTuv/C4 - Λguv + Ruv)/guv = R Now R can be switched for (X,Y,Z) as R2 = ∇2 = d2/dx2 + d2/dy2 + d2/dz2 Thus -2(8πGTuv/C4 - Λguv + Ruv)/guv = ∇Einstein Field Equation Next is the Schrodinger equation which can be solved for the Laplace operator coordinates as well. Which can be solved for ∇ as -(2m(iħ(dΨ/dt) - VΨ)/Ψħ)1/2 = ∇Quantum Mechanics Then a merging equation which fuses GR with QM can be made that is ∇2Quantum Mechanics - ∇2Einstein Field Equation = dS2(x,y,z) OR-(2m(iħ(dΨ/dt) - VΨ)/Ψħ) + (2(8πGTuv/C4 - Λguv + Ruv)/guv)2 = dS2(x,y,z) This Yields a Theory of Quantum Gravity directly from Schrodinger's Equation and the Einstein Field Equations. Edited October 10, 2019 by VictorMedvil Quote
OverUnityDeviceUAP Posted October 10, 2019 Report Posted October 10, 2019 (edited) Let's Start with Einstein's Field Equation General Form. Now in order to merge this with Quantum Mechanics via space coordinates we must solve the equation for Radius® which is -2(8πGTuv/C4 - Λguv + Ruv)/guv = R Now R can be switched for (X,Y,Z) as R2 = ∇2 = d2/dx2 + d2/dy2 + d2/dz2 Thus -2(8πGTuv/C4 - Λguv + Ruv)/guv = ∇Einstein Field Equation Next is the Schrodinger equation which can be solved for the Laplace operator coordinates as well. Which can be solved for ∇ as -(2m(iħ(dφ/dt) - Vφ)/φħ)1/2 = ∇Quantum Mechanics Then a merging equation which fuses GR with QM can be made that is ∇2Quantum Mechanics - ∇2Einstein Field Equation = dS2(x,y,z) OR-(2m(iħ(dφ/dt) - Vφ)/φħ) + (2(8πGTuv/C4 - Λguv + Ruv)/guv)2 = dS2(x,y,z) This Yields a Theory of Quantum Gravity directly from Schrodinger's equation and the Einstein Field Equations.I'm pretty sure it doesn't work that way. First of all because QM and GR are more than a Schrodinger equation and one of Einstein's field equations, secondly they aren't compatible in most all situations in which they can be applied so it's not a matter of of putting them both into one equation. Edited October 10, 2019 by OverUnityDeviceUAP Quote
Vmedvil2 Posted October 10, 2019 Author Report Posted October 10, 2019 I'm pretty sure it doesn't work that way. First of all because QM and GR are more than a Schrodinger equation and one of Einstein's field equations, secondly they aren't compatible in most all situations in which they can be applied so it's not a matter of of putting them both into one equation. They seem mathematically compatible in this example here, what do you mean not compatible? Quote
OverUnityDeviceUAP Posted October 10, 2019 Report Posted October 10, 2019 (edited) They seem mathematically compatible in this example here, what do you mean not compatible?How would you apply it? How would you apply it to a quantum chemistry problem. How would it be used any differently than the Schrodinger equation for mapping atomic orbitals? Edited October 10, 2019 by OverUnityDeviceUAP Quote
Vmedvil2 Posted October 10, 2019 Author Report Posted October 10, 2019 (edited) How would you apply it? How would you apply it to a quantum chemistry problem. How would it be used any differently than the Schrodinger equation for mapping atomic orbitals? It just includes the gravity of the orbital is the only difference with the GR Terms being the (1/(2(8πGTuv/C4 - Λguv + Ruv)/guv n(n-1)))2 Edited October 10, 2019 by VictorMedvil Quote
Vmedvil2 Posted October 10, 2019 Author Report Posted October 10, 2019 (edited) Someone Pointed out this needs a correction, I messed up as R is scalar curvature which the Scalar Curvature of 4-D Minkowski space is given by R = −n(n − 1)/r2n = 4 as the space is 4 dimensional for Hyperbolic space or Minkowski space.(1/(2(8πGTuv/C4 - Λguv + Ruv)/guv n(n-1)))2 = r = ∇Einstein Field Equation so, ∇2Quantum Mechanics - ∇2Einstein Field Equation = dS2(x,y,z) OR -(2m(iħ(dΨ/dt) - VΨ)/Ψħ) - (1/(2(8πGTuv/C4 - Λguv + Ruv)/guv n(n-1)))4 = dS2(x,y,z) Which furthermore, you cannot divide by guv thus I will take the inverse matrix guv-1 which guv = guv-1 Thus Corrected versions (1/(2(8πGTuv/C4 - Λguv + Ruv)guv-1/n(n-1)))2 = r = ∇Einstein Field Equation and -(2m(iħ(dΨ/dt) - VΨ)/Ψħ) - (1/(2(8πGTuv/C4 - Λguv + Ruv)guv-1 / n(n-1)))4 = dS2(x,y,z) Edited October 10, 2019 by VictorMedvil Quote
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