OverUnityDeviceUAP Posted December 23, 2019 Report Share Posted December 23, 2019 (edited) x^2+y^2+z^2-(magnitude)x+(direction)y+(direc/2)z+(direc+mag)=0 This gave me 2 z coordinates which I put in + & - in all 4 quadrants one in front of the other. The smaller z coordinate gave the back square, and the larger z coordinate gave me the larger square which i connected into a cube. Inside the cube I placed my 2:00 am of the circle using z2-z1=x,y,z and found the rest of the outer coordinates that connected top bottom and side to side into the net for the sphere inside the cube using (+/-x)-/+(pi/5 for 12:30 am, +/-(pi/4) for 1:00 am, (+/-)pi/3 for 2:30 am & (+/-)pi/2 for 3:00 am Edited December 24, 2019 by OverUnityDeviceUAP Quote Link to comment Share on other sites More sharing options...
OverUnityDeviceUAP Posted December 23, 2019 Author Report Share Posted December 23, 2019 (edited) The rise and run to create the netting is of course equal to x,y,z divudes by the numerator and denominator of the pi ratio and negative that amount (x/22,y/7,z/7), or positive depending on quadrant, for the inverted back coordinates of the sphere. Now we do my lyrical zero one one zero one oh for dicing the sphere into 5 parts where the curved netting and circle slices are connected by the entangled 4th dimensional lines Edited December 24, 2019 by OverUnityDeviceUAP Quote Link to comment Share on other sites More sharing options...
OverUnityDeviceUAP Posted December 23, 2019 Author Report Share Posted December 23, 2019 Putting more spheres at x,-x,y,-y two center diagonals z/2 on bottom quadrant and two z/2 diagonals on top quadrant as the first equation in the OP=2x solving for x is a bit trickier Quote Link to comment Share on other sites More sharing options...
OverUnityDeviceUAP Posted December 23, 2019 Author Report Share Posted December 23, 2019 8 spheres go on the outside of the first, and then 53 (6x8) go on the outside of that for 64 spheres in 64 planck volumes Quote Link to comment Share on other sites More sharing options...
OverUnityDeviceUAP Posted December 24, 2019 Author Report Share Posted December 24, 2019 Quote Link to comment Share on other sites More sharing options...
OverUnityDeviceUAP Posted December 24, 2019 Author Report Share Posted December 24, 2019 (edited) For the frame dragged (length contraction) entangling 4th D gradient vectors, for one sphere there's 5, if we go horizontal instead of diagonal these gradient vectors slice the sphere portions from V(1) 11:00 to 1, V(2) 10 to 2, V(3) 9:00 to 3:00, V(4) 8 to 4, & V(5) 7 to 5 Edited December 24, 2019 by OverUnityDeviceUAP Quote Link to comment Share on other sites More sharing options...
OverUnityDeviceUAP Posted December 24, 2019 Author Report Share Posted December 24, 2019 These cylindrically expanding sphere-slices phase past one another causing time to dilate in declaration of expansion and acceleration one the ratio surpassed 0/n (where black holes form) into negative 1-n/n, 1/2 of the phase time circular strings are expanding and the second half of the phase time they are contracting such as the preons and quarks or electrons or photons they compose Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.