Arithmetic Progression

[Bitupon]

If log [l,x];log[m,x];log[n,x] are in A.P where ‘x’ is not equal to 1 and ‘x’ is positive

Prove that

n^2=(ln)^{log[l,m]}

 

Should I proceed like this---

log[n,x]-log[m,x]=log[m,x]-log[l,x]

But I have found that this way we cannot approach the result.Please suggest me some other way.images/smilies/happy.gif

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Why so much bold red? There's not much point in emphasizing the whole post.