General Chem question!! HELP

[somebody]

Alright, before you read the problem just wanted to make things clear that the problem that i am goona give it to you is a advance REVIEW(advance for me atleast) problem in my book. SO dont think that i am trying to get my homework done here (had some problems in the past with the homework stuff so just want to make clear), its just a review problem before my midterm so it would be nice if you guys give me some good hints :) or steps!!

 

what volume of 0.248 M CaCl2 must be added to 335 ml of 0.186 M KCl to produce a solution with a concentration of 0.250 M Cl-?

 

Easy for you but hard for me! :)

[Jay-qu]

ok, well if you look at the amount of mol and the volumes seperately

 

initially 0.335L and 0.0623mol

your other solution for every L has 0.496mol

 

and it has to equal 0.250M

 

now you could set up an equation

 

0.25 = n/V

 

0.25 = (0.0623 + 0.496V)/(0.335 + V) where V = volume added

 

following through to conclusion V = 87.2mL

 

I skipped a few steps setting up the equation and then solving it so if you dont understand just ask :)

[somebody]

Oh i never tried attepting to solve this problem that way! Thanks man (or woman), it really gave me a hard time. Thanks, I apreciate your help!!

[Jay-qu]

anytime :) (and its man)