alexander Posted May 14, 2006 Report Posted May 14, 2006 This is a thread to practice latex, in case you have no idea what it is, please read our LaTeX tutorial.I will answer all of your questions in that thread as well, please dont post them here, please dont, i will have to move them... Quote
Tormod Posted May 22, 2006 Report Posted May 22, 2006 [math]E=mc^2[/math] About as far as I got. Quote
ronthepon Posted May 23, 2006 Report Posted May 23, 2006 [math]\delta \Delta \frac{x}{\vec{x}} [/math][math]\huge a, b \cancel\delta[/math] god this is a bit nice... [math]\cancel{a}[/math] [math] \delta aa \acute{50} ,\etc[/math] mmmm... so many others to try out! Quote
sanctus Posted May 23, 2006 Report Posted May 23, 2006 [math]f(x)=\int_{-\infty}^x\frac{(e^{-t^2})}{\sqrt{\pi^x}}dt[/math] Quote
ronthepon Posted May 23, 2006 Report Posted May 23, 2006 [math]\huge \int_{a}^{b}{e^{-14x}^{e}}{dx}[/math] Will this work? [math]a^b^c^d^e^f^g^h[/math] staircase! [math]\frac{X^5_G}{A_2}[/math] [math]\huge \frac{1}{\int^{\delta}_{{\delta}{\pi}} {x}^{\frac{987^{\frac{X^5_G}{\int^{a}_{e^{4123}}{x^{\frac{1.24}{L}}}{dx}}}}{\int_{low}^{high}{x^{x^{2e}}dx}}}dx}[/math] I guess some day or the other, this is going to give up on me. Lets see how much more complex I can make this, before it first shows signs of efficiency weakness. Any human wanna solve this expression? No! don't run away! Quote
Pyrotex Posted May 23, 2006 Report Posted May 23, 2006 I guess it is my turn. Lessee... [math]\Large f(t) = \int_{\small x=0}^{\small x=t}\frac{\sqrt{a x^3 + b x + c^2}}{e^{(c\pi x^2)}} dx\\ \normalsize\text{where a, b, c = integers >0}[/math] Cool beans!! Hot ****!! Ultimate power!!Tomorrow... [math]\\ \huge\text{The World!}[/math] Quote
InfiniteNow Posted May 23, 2006 Report Posted May 23, 2006 Cool beans!! Hot ****!! Ultimate power!!Tomorrow... [math]\\ \huge\text{The World!}[/math] Pinky and the Brain reference? Quote
Pyrotex Posted May 23, 2006 Report Posted May 23, 2006 Pinky and the Brain reference?Ahhhh!! Pinky!! There you are!! Quote
InfiniteNow Posted May 23, 2006 Report Posted May 23, 2006 .Brain: There's only one ride that interests me - the incredible thrill ride of taking over the world!Pinky: Mmm, I think there's a height requirement for that ride. Quote
InfiniteNow Posted May 23, 2006 Report Posted May 23, 2006 [LATEX]test(1.\small{01}\normal)={\frac{1}{\infty^\pi} * 14x\sqrt{-1} = \huge{Sweet}[/LATEX] [LATEX]{\infty}Now[/LATEX] :shade: Quote
Pyrotex Posted May 23, 2006 Report Posted May 23, 2006 Well done, Pinky!! You have mathematically proven that no matter where you are on Earth, you are no more than 4 blocks away from the nearest Starbucks! Do you realized what this means?!?!?! It means I can... [math]\huge\text{Take Over the World!!}[/math] Quote
Southtown Posted September 7, 2006 Report Posted September 7, 2006 [math]$\sim a_0 \sim 1\AA{\rm s}^{-2}$[/math]Well that's udderly meaningless. Found it here, per C1ay's news about the dark matter rebuttal.http://arxiv.org/abs/astro-ph/0606216 Quote
Southtown Posted September 12, 2006 Report Posted September 12, 2006 [math]\left( \sum_i \vec{\alpha}_i \cdot \vec{\nabla}_i + \sum_{i \neq j} \beta_{ij} \delta( \vec{x}_i - \vec{x}_j ) \right) \vec{\Psi} = K \frac{\partial}{\partial t} \vec{\Psi} = iKm \vec{\Psi}[/math] Courtesy of Doctordick. =)http://home.jam.rr.com/dicksfiles/Explain/Explain.htm Quote
Fatstep Posted February 25, 2007 Report Posted February 25, 2007 [math]\beta \gamma \ArrowBoldRightShort[/math] Quote
Guest Lambus Posted April 27, 2007 Report Posted April 27, 2007 testing...[math]\frac{d}{dx} © = 0[/math] Quote
Guest Lambus Posted April 27, 2007 Report Posted April 27, 2007 testing...[math]\frac{d}{dx} (x) = 1[/math] Quote
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.