Latex Practice Ground

[Mercedes Benzene]

Just testing out some Latex since I've never really used it before!

 

[math]t=\frac {\bar{x}-\mu}{s/sqrt{n} [/math]

 

[math] 7.77 \pm 1.984\left(\frac{2.28956}{\sqrt{100}}\right) [/math]

 

[math] (7.316,8.224) [/math]

[DougF]

f(x)=int_{-infty}^xfrac{(e^{-t^2})}{sqrt{pi^x}}dt

[DougF]

f(x)=int_{-infty}^xfrac{(e^{-t^2})}{sqrt{pi^x}}dt

[tag]f(x)=int_{-infty}^xfrac{(e^{-t^2})}{sqrt{pi^x}}dt[/tag]

[DougF]

[tag]f(x)=int_{-infty}^xfrac{(e^{-t^2})}{sqrt{pi^x}}dt[/tag]

[tag] f(x)=int_{-infty}^xfrac{(e^{-t^2})}{sqrt{pi^x}}dt [/tag]

 

I think i'm missing somethe here?

[DougF]

I guess I'm not holding my mouth right.

[Mercedes Benzene]

You don't use [tag], you use THE tags latex and /latex

[DougF]

Thanks I'll try one more time! :eek_big:

 

[math] f(x)=\int_{-\infty}^x\frac{(e^{-t^2})}{\sqrt{\pi^x}}dt [/math]

 

 

Thanks: I think I've got it now. :doh:

RED

[alexander]

[math]f(x)=\int_{-\infty}^x\frac{(e^{-t^2})}{\sqrt{\pi^x}}dt[/math]

[CraigD]

A Feynman diagram, without the pretty wavy line...

 

[math]

 

setlength{unitlength}{1mm}

 

begin{picture}(0, 0)

 

put(10, 20){ makebox(3,0)[cc]{$gamma$} vector(1,0){10} }

 

put(24, 20){ vector(2,1){10} }

 

put(24, 20){ vector(2,-1){10} }

 

put(35, 25){ makebox(3,0)[cc]{$e^-$} vector(2,-1){10} }

 

put(35, 15){ makebox(3,0)[cc]{$e^+$} vector(2,1){10} }

 

put(50, 20){ makebox(3,0)[cc]{$gamma$} vector(1,0){10} }

 

end{picture}

 

[/math]

[tierradelfuego]

[math]-1 = e^{\pi i}[/math]

[alexander]

please use the the math tags....

 

instead of [math]-1=e^{\Pi i}[/math]

[math]-1=e^{\pi i}[/math]

 

use [math]-1=e^{\Pi i}[/math]

[math]-1=e^{\pi i}[/math]

 

distinct advantages of the second over the first are:

you can now click on the expression to see the code

you can notice better rendering and space management

you can now do a load more with this then you were able to with latex... you can do stuff like this:

[math]I(z) = \sin( \frac{\pi}{2} z^2 ) \sum_{n=0}^\infty\frac{ (-1)^n \pi^{2n} }{1 \cdot 3\cdots (4n + 1) } z^{4n + 1}-\cos( \frac{\pi}{2} z^2 ) \sum_{n=0}^\infty\frac{ (-1)^n \pi^{2n + 1} }{1 \cdot 3\cdots (4n + 3) } z^{4n + 3}

[/math]

 

[math]

\setlength{\unitlength}{1mm}

\begin{picture}(60, 40)

{\put(30, 20){\vector(1, 0){30}}}

{\put(30, 20){\vector(4, 1){20}}}

{\put(30, 20){\vector(3, 1){25}}}

{\put(30, 20){\vector(2, 1){30}}}

{\put(30, 20){\vector(1, 2){10}}}

\thicklines

\put(30, 20){\vector(-4, 1){30}}

\put(30, 20){\vector(-1, 4){5}}

\thinlines

\put(30, 20){\vector(-1, -1){5}}

\put(30, 20){\vector(-1, -4){5}}

\end{picture}

[/math]

 

i gotta go find if i can enable the pst-plot module.... that would be interesting

[snoopy]

testing

 

[math]f(x)=\int_{-\infty}^x\frac{(e^{-t^2})}{\sqrt{\pi^x}}dt[/math]

 

 

Ah I see....

 

said the blind man

[snoopy]

[math]\fontsize=10\setlength{\unitlength}{1mm}\begin{picture}(60,40)\end{picture}[/math]

 

[math]y=mx+c[/math]

[snoopy]

[pigeon_soup]

frac{dy}{dy} = fract {9}{32} (x^2 -4x)

[pigeon_soup]

frac{dy}{dy} = fract {9}{32} (x^2 -4x)

[CraigD]

[math]\frac{dy}{dy} = \fract {9}{32} (x^2 -4x)[/math]

 

doesn't parse correctly due to the unrecognized element "fract":

[math]\frac{dy}{dy} = \fract {9}{32} (x^2 -4x)[/math]

 

[math]\frac{dy}{dy} = \frac{9}{32} (x^2 -4x)[/math]

 

renders as:

[math]\frac{dy}{dy} = \frac{9}{32} (x^2 -4x)[/math]

 

There's also an older tag, [math], but it renders less nicely, and supports less LaTeX than the [math] tag.

 

Using LaTeX in your posts shows attention to detail, which will win the admiration of your peers! :)