somebody Posted July 17, 2006 Report Share Posted July 17, 2006 i came across a problem in my practice exam that i could not figure out so i was hoping you guys can help me out! here is the problem: a fan is to accelerate quiescent air to a velocity of 10 m/s at a rate of 4m^3/s. Determine the minimum power that must be supplied to the fan. Take the density of air to be 1.18 kg/m^3.(Answer=236 W) Thank You Quote Link to comment Share on other sites More sharing options...
Jay-qu Posted July 17, 2006 Report Share Posted July 17, 2006 Power=Energy per Second So the fan must accelerate 4.72kg of air to 10m/s per second. Energy needed to accelerate a mass 'm' to velocity 'v' is: 0.5*m*(v^2) see how you go with that, if you have any more problems just ask :moon: Quote Link to comment Share on other sites More sharing options...
somebody Posted July 17, 2006 Author Report Share Posted July 17, 2006 wow, i was doing the same thing but could not figure out how to get ride of second from kg/s thanks ! Quote Link to comment Share on other sites More sharing options...
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