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# Neutrons bombard nuclei of N(14,7) converting it into Li(7,3). The process is accompanied by the emission of:

1)4 protons and 4 neutrons

2)6 protons and 2 electrons

3)1 alpha particle, 2 protons and 1 neutron

4)2 alpha particles and gamma ray photon

I get 2 solutions here.

N(14,7) + n(1,0) ---> Li(7,3) + 4p(1,1) + 4n(1,0)

N(14,7) + n(1,0) ---> Li(7,3) + 2(alpha particles) + (gamma rays)

 

Is it right? When N(14,7) is bombarded with a neutron, is the emission of 2 different set of particles possible? Here N=nitrogen, Li=Lithium, n=neutron, p=proton.

Posted

I would say that it is number 4, the protons and neutrons will not be emmited seperately. But I have some doubt as to whether a gamma ray would be emmited because Li is less stable than N.. possibly require more energy to hold the nucleus together.

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