Moonchild Posted November 16, 2004 Report Posted November 16, 2004 OK, so from the equation PE+KE=E(mechanical), we can derive the following equation: h=v^2/2g Under what conditions/events does this scenario apply? What if the equation were 2=phi*v^2/gh? What would an object's path look like? How would the phi affect the height or velocity?
Bo Posted November 17, 2004 Report Posted November 17, 2004 OK, so from the equation PE+KE=E(mechanical), we can derive the following equation: h=v^2/2g Under what conditions/events does this scenario apply? there are 3 assumptions made in such a derivation:- The kinetic energy is given by 1/2 m v^2- the potential energy is given by m g h- no energy is lost. and it describes a particle falling downword, with constant accelarationg g, and perhaps moving with a constant speed in the horizontal direction epecially the point about the potential energy can be altered a bit, e.g. if e include some friction, a form for the potential could be ~ mgh - K v ; where K is some constant. Alterations in the path of the particle would be that the acceleration isn't constant anymore. Bo
Recommended Posts