The Roulette Conundrum

[LaurieAG]

By the same ratio, two consecutive zeros is nearly three times more likely than than two zeros separated by exactly 36 other numbers.

 

And three consecutive zeros is much more likely than three zeros separated by exactly 36 other numbers etc.

[Simon]

And three consecutive zeros is much more likely than three zeros separated by exactly 36 other numbers etc.

 

Actually, I'm not sure how you define three zeros separated by exactly 36 other numbers. Do you mean exactly 36 other numbers on both sides of the middle zero? Or exactly 36 other numbers between the first and third zero, with the middle zero occuring somewhere between?