HHSM Posted November 3 Report Posted November 3 (edited) I have approximated Goldbach's Problem (that all even numbers above 2 can be constructed with 2 primes) for a sequence from 4 to 100 using brute force and ignorance. Jokes aside, I used the Sieve of Eratosthenes and wrote down the results on the sum table below. In addition, I decided to plot the sum's numbers on two planes. The first plots formed an exponential curve, with a bell curve in the number 79. For the second plots, I took the values of the second numbers and plotted them as isolated points on the Y-axis, connecting them and smoothing the lines, forming bell curves. 2+2 =4 3+3 =6 5+3=8 5+5=10 5+7=12 7+7=14 13+3=16 13+5=18 17+3=20 19+3=22 19+5=24 23+3=26 23+5=28 23+7=30 29+3=32 29+5=34 29+7=36 31+7=38 37+3=40 37+5=42 37+7=44 43+3=46 43+5=48 47+3=50 47+5=52 47+7=54 53+3=56 53+5=58 53+7=60 59+3=62 59+5=64 59+7=66 61+7=68 67+3=70 67+5=72 71+3=74 73+3=76 73+5=78 73+7=80 79+3=82 79+5=84 79+7=86 83+5=88 83+7=90 89+3=92 89+5=94 89+7=96 79+19=98 97+3=100 Edited November 3 by HHSM some parts of the sum table was wrong Moontanman 1 Quote
OceanBreeze Posted November 4 Report Posted November 4 Nice work. Now, just for fun, try to consider other possibilities: 10 = 5 + 5 = 3 + 7 14 = 7 + 7 = 3 + 11 16 = 13 + 3 = 5 + 11 18 = 13 + 5 = 11 + 7 20 = 17 + 3 = 13 + 7 22 = 19 + 3 = 11 + 11 etc…. It gets more interesting as you find more possible combinations. Quote
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