arkain101 Posted December 24, 2006 Report Posted December 24, 2006 I am working on something that appears to explain the fundamental constants, with logic, geometric & mathamatical expression. Included is an image of the fundamental geometric expression. It is postulated all events (ie, force, energy, motion) are products between two frames. We call all frames a closed system. The first closed fundamental shape is a 3 sided-cornered trigangle. (We use a right triangle for simplicity) The relationship or ratio between two frames that are able to form an event is a squared relationship. The events that form between two frames are valued, placed, or expressed through the hypotenuse of the triangle. Example; a force between two frames is a force that we observe to act in a strait line (aka the shortest distance between two points). This is observation via hypotenuse. Note that hypotenuse is infact the producer of a constant (ie distance= pythagoras constant). Thus anything that acts via hypotenuse between two frames has a constant value. This is light, and other constants in nature, or that which travels through the strait line of hypotenuse between two frames, that create an event. As distance between the two frame changes (aka the hypotenuse shrinks) each x,y plane as it were of the triangle changes equally. Lets look at the fine structure constant.[math]\alpha = \frac {e^2}{\hbar c}[/math] We see that c : is a value produced by a square root of these measurments. A square root of a value produces a positive + and a negative - answer, that is two answers, The x & y sides of the triangle per say that is part of the Closed system. The plank length is the square root of 3 funamental constants. [math]\hbar[/math](pronounced h-bar) is Dirac's constant, Planck's constant divided by 2π ; G is the gravitational constant; c is the speed of light in vacuum. In other words alike our triangle, the square root of these 3 hypotenuse (constants) produces two values of length (equal lenghts) for our right triangle x, y plane. the plank length is either the 4th hyotenuse of this relatioship or a equal value for x and y of a fundamental triangle. (im too fatigued to elaborate this much clearer at this point) cwes99_03 1 Quote
arkain101 Posted December 26, 2006 Author Report Posted December 26, 2006 When we look at the lorentz, and the fact that we end up with two answers when using a square root. [math]\gamma (+)[/math][math]\gamma (-)[/math] We see that we can re-express this equation as [math]\gamma = \frac {1}{\left (1- \frac {v^2}{c^2}\right )^{\,1/2}}[/math] and in doing so we arive at the proper expression of modeling the universe in mathamatics. We get an answer for 1 frame that is 1/2 of the whole system (1). The lorentz transformation as this; ..suggests there is null result for the one frame(in motion, due to the + and - result of a square root) or equal opposite dilations for each frame of the system [math]^b[/math]. However, the latter [math]^b[/math] does not appear to be the case. As we see the frame at rest [math]^a[/math] appears to remain constant, while the frame in motion [math]^b[/math] undergoes all the proposed dilations. Thus, the proper lorentz transformation should use the [math]^{\,1/2}[/math]that is,[math]\gamma = \frac {1}{\left (1- \frac {v^2}{c^2}\right )^{\,1/2}}[/math] with this we can see why [math]x^2[/math] [math]x^1[/math] [math]x^{\,0.5}[/math] or [math]x^{\,1/2}[/math] are the 3 functions of powers found in any one event.note [math]{\,1/2}[/math] is used to replace [math]\sqrt x[/math] For example; a position of a body in respect to an observer is written in this formulation. The observer is part of the system to develope the position.thus the position and the observer are infact two points on the graph. And through this system there is two sets of triangulation, in repsect to the position relative to each frame. As so we dicover each frame is 1/2 of the system. A simple explainaton of this; [math]mv^2[/math] is the whole system. when dealing with measuring one frame you deal with 1/2 of the system. note that + and - only mean for opposing energy. [math]+K_e = 1/2 \left (mv^2 \right )[/math] This is only 1/2 of the system in which momentum of each frame is involved in the interaction. So thus we do arrive with a negitive Ke for the object that is going to have 'work' applied to it[math]-K_e = 1/2 \left (mv^2 \right )[/math] Where we see, [math]K_e_(total) = mv^2[/math] The Kinetic energy total is of course a null result. That is the total energy does not change, but the state of energy of the system changes in and equal and opposite fashion.and as such supports discription of the universe being a closed system, where nothing is lost or destroyed, but only changes form. I stumbled upon a website that is working with a similar concept. Quite interesting. Dr Milo Wolff: The Wave Structure of Matter (Electron): Origin of the Laws of Nature And in any shape, which is 'a closed system', contains a constant. I propose that a closed system of the permeabiltiy and permittivity of space forms a 'shape' as it were and is exactly where the constant comes from. However, I leave open the possibilty that the speed of light is not a constant in the formal definition. Quote
Qfwfq Posted December 28, 2006 Report Posted December 28, 2006 We see that we can re-express this equation as [math]\gamma = \frac {1}{\left (1- \frac {v^2}{c^2}\right )^{\,1/2}}[/math] and in doing so we arive at the proper expression of modeling the universe in mathamatics.And we can also express it as: [math]\gamma = \left (1- \frac {v^2}{c^2}\right )^{-\frac12}[/math] So, what's the essential difference? Quote
arkain101 Posted December 28, 2006 Author Report Posted December 28, 2006 To understand more about what occurs in each frame. Square root I think suggests two sets of gamma dilation. 1/2 suggests one gamma for one frame. I am stating that the power value 1/2, 1, and 2 infact directly relates to how many frames form the system. E=MC^2 for example, if correct, suggests two frames to create light. theoretically. Quote
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