arkain101 Posted January 11, 2007 Report Posted January 11, 2007 Strait to it. Here is the example. On earth there is an observer looking at a clock that is at rest out in space 1 light year away. The clock reads 12:00 (be it digital or a clock with hands). We can easily show that the clocks time at its location is 12:00 + 1 year. So as the clock moves towards us My question is, does the time it displays speed up in relation of the contracting distance between the observer and the clock? and if so what kind of equation would show how to calculate this change? (including a clock moving away from the observer). Quote
Jay-qu Posted January 11, 2007 Report Posted January 11, 2007 Imagine the clock is synched with one on earth so that they both read 12 but mearly a year apart, as the other clock gets closer if it travels at a very slow velocity (so time dilation can be ignored) when it eventually gets to earth both clocks must now read the same time. This means that the clock must have appeared to speed up, this is because as the clock moves each successive light wave sent out will be closer to the previous one and hence take less time to arrive. Quote
Farsight Posted January 11, 2007 Report Posted January 11, 2007 arkain: if you search google on light doppler and maybe clock you ought to find what you're looking for. Maybe this does it: SpringerLink - Journal Article but it's aethery and big - I haven't downloaded it myself, so maybe not. You might find something easier on wikipedia: Doppler effect - Wikipedia, the free encyclopedia Quote
arkain101 Posted January 12, 2007 Author Report Posted January 12, 2007 Thank you for the replies. What I am trying to show is that distance is related to time dilation, and may counteract certain SR effects. Such as a clock moving towards an observer will observe to speed up in the observers frame, and a clock moving away will tend to slow down in the observers frame. Where as SR works with velocity as always slowing observation of clocks/time. This equation: Is I think part of what I am trying to formulate. Quote
arkain101 Posted January 12, 2007 Author Report Posted January 12, 2007 cont'd :That this geometric expression is paradoxical(?) in itself, and breaks the rules of SR to explain SR gif: http://upload.wikimedia.org/wikipedia/en/e/eb/Time_dilation02.gif Paradox because, It takes two seperate frames and makes them one, and attempts to describe how a dilation might occur in such a situation. Quote
Janus Posted January 12, 2007 Report Posted January 12, 2007 Relativistic Doppler Effect: Relativistic Doppler Effect Quote
LaurieAG Posted January 21, 2007 Report Posted January 21, 2007 On earth there is an observer looking at a clock that is at rest out in space 1 light year away. The clock reads 12:00 (be it digital or a clock with hands). We can easily show that the clocks time at its location is 12:00 + 1 year. So as the clock moves towards us My question is, does the time it displays speed up in relation of the contracting distance between the observer and the clock? and if so what kind of equation would show how to calculate this change? (including a clock moving away from the observer). Interesting arkain101. (1) If the clock was stationary we should see the normal flow of time. (2) If the clock was moving at the speed of light we should see all of the light from all the different times at the same time as when the clock reached the observer. In between (1) & (2) the perceived speed up of time is in proportion to the ratio of the speed of the clock(in light years)/the speed of light. (3) If the clock was moving away from the observer at the speed of light, the first light would arrive after 1 year. At this point it would take 2 years for the light from the clock faces current position to arrive at the observer (arriving when the clock was 4 light years away) etc. This is a very large (if not infinite) progression which, incidentally, is very similar to what would happen to an object dissapearing into a black hole. i.e. the clock would get slower and slower to the observer. Quote
arkain101 Posted January 21, 2007 Author Report Posted January 21, 2007 Yes the methods used to describe time dilation in special relativity appears to break the foundations it is built upon. By visualising a photon inside anothe frame bouncing between mirrors as a clock, you have to remove yourself from your frame of observation and place yourself inside the frame of the ship with the clock. The photon that forms the clock is impossible to see unless it traveses the distance to reach the stationary observer. Thus the geometry to express this concept appears false in respect to relativities truth basics. That is, you are restricted to your own frame and that of which is at rest relative to you. And your present moment is that of your posistion. If we invision the universe as a simple two object design. We see that if the objects are traveling towards eachother, they can each claim they are at rest while the other is in motio, or they can each claim they are in motion while the other is at rest, or they can each claim they are both moving. It is one and the other, and neither, and both at the same time. The very foundations of quantum theory as I understand was built upon this realisation of the effects with the double slit experiment with light and electrons. The two objects in this universe are always connected by radiation (black body radiation). Nor could they ever be seperated from this continuum of exhanging energy, that displays the passage of time, and change, and position. As such the inertia of one object at rest is rightly so the motion of that same object, while not being comprehended, while the object in motion is rightly so the object at rest with inertia. There is no proof as to which object is which, and as such, any change is equal upon both objects at the same time simunatiniously and equally. The only difference the objects can create between eachother is the independent rotational velocity and direction of that spin. So it appears even in the macroscopic range of things, quantum physics is at hand. Quote
Bombadil Posted January 21, 2007 Report Posted January 21, 2007 Then if two clocks are set to the same time and then at a latter time they are compared no mater the paths they take between when they are set to each other and when they are compared the two clocks must read the same time. So time dilation has no effect on the time the clocks read?Is this also true for any effect that gravity might have on the clocks? Quote
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